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2 years ago

6

Fig. 19-4 shows two wires, in cross section, carrying 7.0 Amperes out of the page. Determine the total magnetic field, due to bo

th wires, at point X midway between the wires.

1 answer:

mel-nik [20]2 years ago

6 0

I habe no idea i just need points sorry

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Which of these diagrams best represents the steps in the formation of planets?

sineoko [7]

The right answer for the question that is being asked and shown above is that: "<span>C) The clouds of dust and gases rotate at high speed > The clouds condense > The sun is born > The planets are born " This is the </span><span>diagram that best represents the steps in the formation of planets</span>

6 0

1 year ago

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The ends of a massless rope are attached to two stationary objects (e.g., two trees or two cars) so that the rope makes a straig

Virty [35]

Answer:

1. The tension in the rope is everywhere the same.

2. The magnitudes of the forces exerted on the two objects by the rope are the same.

3. The forces exerted on the two objects by the rope must be in opposite directions.

Explanation:

"Massless ropes" do not have a<em> "net force"</em> which means that it is able to transmit the force from one end of the rope to the other end, perfectly. It is known for its property of having a total force of zero. In order to attain this property, the magnitude of the forces exerted on the two stationary objects by the rope are the same and in opposite direction. <u>So this explains number 2 & 3 answers.</u>

Since the objects that are held by the rope are stationary, then this means that the tension in the rope is also stationary. This means that the tension in the rope everywhere is the same (provided that the rope is still or in a straight line, as stated in the situation above, and is being held by two points). <u>So, this explains number 1.</u>

6 0

1 year ago

Suppose that you measure the intensity of radiation from carbon-14 in an ancient piece of wood to be 6% of what it would be in a

borishaifa [10]

Answer:

t = 23136 years old

Explanation:

The intensity of radiation obeys the exponential decay law.

$I(t)=I_{0}e^{-\lambda t}$ (1)

Here:

λ is the radiation decay constant.

I is the intensity of radiation after t time.

I₀ is the initial intensity of radiation.

t is the time

Now, we know that the intensity of radiation is a 6% of what it would be in a freshly cut piece of wood, in other words:

$I(t)=0.06I_{0}$ (2)

Combining (2) with (1), we have:

$0.06I_{0}=I_{0}e^{-\lambda t}$

$0.06=e^{-\lambda t}$ (3)

Now, we just need to solve (3) for t.

$t=\frac{-ln(0.06)}{\lambda}$ (4)

and $\lambda = \frac{ln(2)}{t_{1/2}}$ (5)

$t_{1/2}$ is the half-life.

In our case, we have ¹⁴C, so the $t_{1/2} = 5700 y$

Finally, we can find t putting (5) in (4):

$t=\frac{-t_{1/2}ln(0.06)}{ln(2)} = 23136 y$

I hope it helps you!

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2 years ago

The frequency of the middle d note on a piano is 293.66 hz. what is the wavelength of this note in centimeters? the speed of sou

Natali5045456 [20]

Wavelength = speed of sound / frequency

= (343.06 m/s) / (261.63 Hz)

= 1.31 m (or 131 cm)

4 0

1 year ago

An object is released from rest at a height h. During the final second of its fall, it traverses a distance of 38m. Determine th

nadezda [96]

Gravity is 9.8 m/s² means means every second distance travelled
increases by the distance in the previous second plus an extra 9.8m
during last second it fell 38m
previous second dist = 38 - 9.8m = 28.2
previous second = 28.2 - 9.8m = 18.4m
distance left = 18.4 - 9.8m = 8.6m
(so actually less than a second as it only travelled 8.6m)
total distance h = 38 + 28.2 + 18.4 + 8.6 = 93.2m

hope this is what is required

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2 years ago

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