Answer:
The frequency is 
Explanation:
From the question we are told that
The time taken for it to decay to half its original size is 
Let the voltage of the capacitor when it is fully charged be 
Then the voltage of the capacitor at time t is said to be 
Now this voltage can be mathematical represented as
Where RC is the time constant
substituting values
Generally the cross-over frequency for a low pass filter is mathematically represented as
substituting values
The mass of the puck is
m = 0.15 kg.
The diameter of the puck is 0.076 m, therefore its radius is
r = 0.076/2 = 0.038 m
The sliding speed is
v = 0.5 m/s
The angular velocity is
ω = 8.4 rad/s
The rotational moment of inertia of the puck is
I = (mr²)/2
= 0.5*(0.15 kg)*(0.038 m)²
= 1.083 x 10⁻⁴ kg-m²
The kinetic energy of the puck is the sum of the translational and rotational kinetic energy.
The translational KE is
KE₁ = (1/2)*m*v²
= 0.5*(0.15 kg)*(0.5 m/s)²
= 0.0187 j
The rotational KE is
KE₂ = (1/2)*I*ω²
= 0.5*(1.083 x 10⁻⁴ kg-m²)*(8.4 rad/s)²
= 0.0038 J
The total KE is
KE = 0.0187 + 0.0038 = 0.0226 J
Answer: 0.0226 J
A cold acetic acid solution is used to wash the residue of
the reagent in preparation of an aldol condensation product after vacuum
filtration. The main reason in washing
with the acetic acid rinse is to neutralize any sodium hydroxide.
As per given equation we have
now as per the dimensional analysis we can say that dimension of right side of equation must be equal to left side of the equation
now as per left side of equation its dimension is same as length or meter
now we can say it should be meter on right side also
similarly for other term we have
<em>so above are the dimensions of b and c</em>
You want v2 = v1 + at
v is measured in m/s, a in m/s2, and t in s.
the dimensions multiply like algebraic quantities.
so because v2 is measured in m/s, then (v1 + at) has to come out in m/s
the units for (v1 + at) are (m/s) + (m/s2)(s)
time "s" cancels out one acceleration "s", so it comes ut to (m/s) + (m/s), which = (m/s).
if you had (v1t + a), then you would have (m/s)(s) + (m/s2) which = (m) + (m/s2), which doesn't work.
