A disk of known radius and rotational inertia can rotate without friction in a horizontal plane around its fixed central axis. T
1 answer:
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Answer:
The magnitudes of the net magnetic fields at points A and B is 2.66 x T
Explanation:
Given information :
The current of each wires, I = 4.7 A
dH = 0.19 m
dV = 0.41 m
The magnetic of straight-current wire :
B= μI/2πr
where
B = magnetic field (T)
μ = 1.26 x
(N/
)
I = Current (A)
r = radius (m)
the magnetic field at points A and B is the same because both of wires have the same distance. Based on the right-hand rule, the net magnetic field of A and B is canceled each other (or substracted). Thus,
BH = μI/2πr
= (1.26 x )(4.7)/(2π)(0.19)
= 4.96 x T
BV = μI/2πr
= (1.26 x )(4.7)/(2π)(0.41)
= 2.3 x T
hence,
the net magnetic field = BH - BV
= 4.96 x - 2.3 x
= 2.66 x T
Answer:
(a). The deflection angle is
(b). The deflection angle is
(c). The deflection angle is
Explanation:
Given that,
Mass of earth
Radius of earth
Mass of white dwarf
Radius of white dwarf
Mass of Neutron
Radius of neutron
We need to calculate the deflection angle for earth
Using formula of angle
Where, R = radius
G = gravitational constant
M = mass
c = speed of light
Put the value into the formula
The deflection angle is
We need to calculate the deflection angle for white dwarf
Using formula of angle
Put the value into the formula
The deflection angle is
We need to calculate the deflection angle for neutron star
Using formula of angle
Put the value into the formula
The deflection angle is
Hence, This is the required solution.