All categories

2 years ago

During action potential, the electrical charge inside the neuron is __________ the electrical charge outside the neuron.

2 answers:

7 0

During action potential, the electrical charge inside the neuron is positive compared to the electrical charge outside the neuron.

FromTheMoon [43]2 years ago

5 0

<span>The correct answer is: Positive compared to

Explanation:
An action potential is the process that happens when a neuron fires a signal. During the action potential, part of the neural membrane opens to allow positively charged ions inside the cell and negatively charged ions out; consequently, the positive charge inside the neuron increases during that process. In a nutshell, during an action potential, the electrical charge inside the neuron is positive compared to the electrical charge outside the neuron.</span>

You might be interested in

Difference between calorimeter and thermometer ?

Kaylis [27]

A calorimeter is can be used to measure the amount of heat released or involved in a chemical reaction. Whereas thermometer can only measures temperature or hotness of a substance. It cannot be used to measure the thermal rate or amount of heat energy of a reaction.

6 0

2 years ago

Read 2 more answers

CHEGG 42 mT magnetic field points due west. If a proton of kinetic energy 9 x 10-12 J enters this field in an upward direction,

alexdok [17]

Answer:

The magnitude of the Force is $F = 697 *10^{-15}N$ and the direction is South

Explanation:

From the question we are told that

The magnetic field point due west and since East point toward the positive x -axis $(i)$ then this magnetic field would be mathematically represented as

$\= B = 42(-i)mT = 42*10^{-3} (-i) T$

Now from the question we are told that the kinetic energy is

$KE = 9*10^{-12}J$

Now this kinetic energy can be mathematically represented as

$KE = \frac{1}{2}mv^2$

Where m is the mass of proton which has a general value of

$m = 1.67*10^{-27}kg$

Now making the subject of the formula

$v = \sqrt{\frac{KE}{0.5 * m} }$

Substituting values we have

$v = \sqrt{\frac{9*10^{-12}}{0.5 * 1.67*10^{-27}} }$

$= 10.37*10^7m/s$

Now from the question we are told that proton is moving upward which is in the positive z direction so the velocity of the proton would be in the positive

So the velocity would be

$\= v = 10.37*10^{7} \r k \ m/s$

Now the magnetic Force can be mathematically represented as

$\= F = q \= v * \= B$

Where q is the charge on the proton which has a general value of $q =1.6*10^{-19}C$

Now substituting the value

$\= F = 1.6*10^{-19 } * (10.37 *10^7) \r k * (42 *10^{-3})(-i)$

$= 697*10^{-15} J$

Now according to Fleming's left hand rule the direction of the magnetic force is south toward the negative Y - direction $(-j)$

So the force can be denoted as

$\= F = 697*10^{-15}(-j) N$

6 0

2 years ago

An object is located 25.0 cm from a convex mirror. The image distance is -50.0 cm. What is the magnification?

Lynna [10]

Answer:

$\boxed{\sf Magnification \ (m) = 2}$

Given:

Object distance (u) = 25.0 cm

Image distance (v) = -50.0 cm

To Find:

Magnification (m)

Explanation:

$\boxed{\bold{\sf Magnification \: (m) = - \frac{Image \: distance \: (v)}{Object \: distance \: (u)}}}$

Substituting values of Image distance(v) & Object distance (u) in the equation:

$\sf \implies m = - \frac{( - 50)}{25}$

-(-50) = 50:

$\sf \implies m = \frac{50}{25}$

$\sf \implies m = \frac{2 \times \cancel{25}}{ \cancel{25}}$

$\sf \implies m = 2$

4 0

2 years ago

what did classical physics predict about electron flow as a result of light shining on a metal surface?

stiv31 [10]

This looks like the photo electric effect ... classical physics reckoned that if you shone an intense enough light beam on a metal you could get electrons ejected from the metal (maybe in analogy to thermionic emission - heat). It sort of "forgot" about the frequency and photon/particle nature of light.
Enter the "photo electric" effect experiment, Einstein's explanation, and the Nobel committee having an excuse to award E a Nobel prize, even though said prize was probably more for relativity.

8 0

2 years ago

The circuit below represents four resistors connected to a 12-volt source. What is the total current in the circuit? 4.0Ω 6.0Ω 1

Tpy6a [65]

Answer:

For series connected resistors I = 0.5A

For parallel connected resistors I = 8.5A

Explanation:

Since the diagram is not available, our solution will be divided into two;

According to ohm's law which states that "the current passing through a,metallic conductor at constant temperature is directly proportional to the potential difference across its ends. Mathematically, E = IRt where;

E is the electromotive force

I is the total current in the circuit

Rt is total equivalent resistance.

Where E = 12volts

Rt can be gotten depending on the arrangements of the resistors which can either be in series or parallel.

If the resistors are in series, their equivalent resistance gives;

Rt = 4.0Ω+6Ω+8Ω+6Ω

Rt = 24Ω

The current I will be;

I = E/Rt = 12/24

I = 0.5A

If the connection is in series, the total current in the circuit will be 0.5A.

For resistance in parallel;

1/Rt = 1/4Ω+1/6Ω+1/8Ω+1/6Ω

1/Rt = 6+4+3+4/24

1/Rt = 17/24

Rt = 24/17Ω

I = E/Rt

I = 12/(24/17)

I = 12×17/24

I = 8.5A

If the connection is in parallel, the total current in the circuit will be 8.5A

8 0

2 years ago

Read 2 more answers