I believe the answer is #4. u can always ask google if u believe that's the wrong answer :)
The turns ratio is the factor that determines voltage andcurrent. In order to have the same current across the resistorin the primary as the resistor in the secondary, then:--N(p) = Primary turnsN(s) = Secondary turnsR(2) = Primary resistorR(1) = Secondary resistor--R(2)/R(1) = N(p)/N(s)R(2) = R(1)*(N(p)/N(s))--If arbitrary values are plugged in, you will see that this step up transformer will require 2x the resistance required in the secondary, R(1), to obtain the same current. Thus R(2) will be 1/2 the value of R(1). This is due to the stepped up voltage in the secondary.
<h2><u>Answer:</u></h2>
The simulation kept track of the variables and automatically recorded data on object displacement, velocity, and momentum. If the trials were run on a real track with real gliders, using stopwatches and meter sticks for measurement, the data compared by the following statements:
1. (There would be variables that would be hard to control, leading to less reliable data.)
3. (Meter sticks may lack precision or may be read incorrectly.)
4. (Real glider data may vary since real collisions may involve loss of energy.)
5. (Human error in recording or plotting the data could be a factor.)
<h3><u>Answer;</u></h3>
<em>B. Sound waves can move through various mediums.</em>
<h3><u>Explanation;</u></h3>
- <em><u>A wave is a transmission of a disturbance from one point to another</u></em>. It involves transmission of energy from the source to another point.
- <u><em>A wave may or may not require a medium for transmission.</em></u> Waves that require medium for transmission are called <em><u>mechanical waves </u></em>and those that do not require medium for transmission are known as <em><u>electromagnetic waves</u></em>.
- <em><u>Light is an example of electromagnetic wave therefore it can be blocked when obstacles are placed on its path.</u></em> However, for the case of sound waves, they can not be blocked by an obstacle as sound would travel through the medium used to block.
<span>Use the kinematic equation vf^2 = vi^2 + 2ad where;
vf = ?
vi = 0 m/s
a = 9.8 m/s^2
d1 = 10 m
d2 = 25 m
final velocity at the ground (d1): vf = sqrt(2)(9.8)(10) = 14 m/s
final velocity to the bottom of the cliff (d2): vf = sqrt(2)(9.8)(25) = 22.14 m/s
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