Answer:
16.68 L
Explanation:
First of all, we need to calculate the number of moles corresponding to 25.2 g of CO2.
The molar mass of CO2 is 44.01 g/mol, therefore the number of moles is:
So now we can use the ideal gas equation:
where:
p = 0.84 atm is the gas pressure
V = ? is the volume
n = 0.573 mol is the number of moles
R = 0.08206 L atm / K mol is the gas constant
T = 25°c = 298 K is the gas temperature
Substituting into the equation and re-arranging it, we find the volume:
The answer in the blank is that it is difficult to accelerate at decelerate the vehicle when it is on a fast speed because having a fast speed makes it difficult to adjust the meter as well as if you try to decelerate the vehicle, it could burn out the tires and engine as it is in the fast speed, in accelerating it, it could also be complicated because it would only make the car faster enough that you may no longer control of how to stop it.
Most ejections originate from active regions on the Sun's surface, such as groupings of sunspots associated with frequent flares. These regions have closed magnetic field lines, in which the magnetic field strength is large enough to contain the plasma.
Answer:
a) 
b) 
c) 
Explanation:
<em><u>The knowable variables are </u></em>
Since the three traffic signs are <u>equally spaced</u>, the <u>distance between each sign is 
</u>
a)
b)
Since we know the velocity in two points and the time the car takes to pass the traffic signs
c)
This problem has three questions I believe:
>
How hard does the floor push on the crate?
<span>We have to find the net
vertical (normal) Fn force which results from Fp and Fg.
We know that the normal component of Fg is just Fg, which is equal to as 1110N.
From the geometry, the normal component of Fp can be calculated:
Fpn = Fp * cos(θp)
= 1016.31 N * cos(53)
= 611.63 N
The total normal force Fn then is:
Fn = Fg + Fpn
= 1110 + 611.63
=
1721.63 N</span>
> Find the friction
force on the crate
<span>We
have to look for the net horizontal force Fh which results from Fp and Fg.
Since Fg is a normal force entirely, so we can say that the
horizontal component is zero:
Fh = Fph + Fgh
= (Fp * sin(θp)) + 0
= 1016.31 N * sin(53)
=
811.66 N</span>
> What is the minimum
coefficient of static friction needed to prevent the crate from slipping on the
floor?
We just need to compute the
ratio Fh to Fn to get the minimum μs.
μs = Fh / Fn
= 811.66 N / 1721.63 N
<span>=
0.47</span>
