We are given: Final velocity (
)=20 m/s .
Time t= 2.51 s and
distance s = 82.9 m.
We know, equation of motion

Let us plug values of final velocity, and time in above equation.


Subtracting 2.51a from both sides, we get
-----------equation(1)
Using another equation of motion

Plugging values of vi =20-2.51a, t=2.51 and distnace s=82.9 in this equation.
We get,

Now, we need to solve it for a.
20-20+2.51a=165.8a.
-163.29a=0
a=0.
So, the acceleration would be 0 m/s^2.
Answer:
I am not a driver, but I think it's C.
Explanation:
Answer: 0.98m
Explanation:
P = -74 mm Hg = 9605 Pa = 9709N/m^2
= 9605 kg m/s^2/m^2
density of water: rho = 1 g/cc = 1 (10^-3 kg)/(10^-2 m)^-3 = 1000 kg/m^3
Pressure equation: P = rho g h
h = P/(rho g)
h = (9605 kg/m/s^2) / (1000 kg/m^3) / (9.8 m/s^2)
h = 0.98 m
0.98m is the maximum depth he could have been.
-- With two resistors in parallel, the total effective resistance is
the reciprocal of (1/R₁ + 1/R₂).
1/R₁ + 1/R₂ = 1/15 + 1/40
= 8/120 + 3/120
= 11/120
So the total effective resistance is 120/11 = 10.9 ohms .
Current = (voltage) / (resistance)
= 12 / (120/11)
= (12 · 11) / 120
= 132/120 = 1.1 Amperes
Answer:
She passes through a loud spot at x = 19.5m from the first speaker. Constructive interference occurs here.
At the quiet spot destructive interference occurs. The minimum distance for this to occur is 20.25 from the first speaker.
Explanation: