Answer:
160 Hz , 240 Hz , 400 Hz
Explanation:
Given that
Frequency of forth harmonic is 320 Hz.
Lets take fundamental frequency = f₁
f₁=80 Hz
Frequency of first harmonic = f₂
f₂=2 f₁
f₂ =2 x 80 = 160 Hz
Frequency of second harmonic = f₃
f₃= 3 f₁=3 x 80 = 240 Hz
Frequency of fifth harmonic = f₅
f₅= 5 f₁= 5 x 80 = 400 Hz
Three frequencies are as follows
160 Hz , 240 Hz , 400 Hz
Answer:
Explanation:
The strain is defined as the ratio of change of dimension of an object under a force:
where
is the change in length of the object
is the original length of the object
In this problem, we have and
, therefore the strain is
The inlet velocity is 1.4 m/s and inlet volume is 0.019 m³/s.
Explanation:
When water entering the tube of constant diameter flows through the tube, it exhibits continuity of mass in the hydrostatics. So the mass of water moving from the inlet to the outlet tend to be same, but the velocity may differ.
As per mass flow equality which states that the rate of flow of mass in the inlet is equal to the product of area of the tube with the velocity of the water and the density of the tube.
Since, the inlet volume flow is measured as the product of velocity with the area.
Inlet volume flow=Inlet velocity*Area*time
And the mass flow rate is
Mass flow rate in the inlet=density*area*inlet velocity*time
Mass flow rate in the outlet=density*area*outlet velocity*time
Since, the time and area is constant, the inlet and outlet will be same as
(Mass inlet)/(density*inlet velocity)=Area*Time
(Mass outlet)/(density*outlet velocity)=Area*Time
As the ratio of mass to density is termed as specific volume, then
(Specific volume inlet)/(Inlet velocity)=(Specific volume outlet)/(Outlet velocity)
Inlet velocity= (Specific volume inlet)/(Specific volume outlet)*Outlet velocity
As, the specific volume of water at inlet is 0.001017 m³/kg and at outlet is 0.05217 m³/kg and the outlet velocity is given as 72 m/s, the inlet velocity
is
So, the inlet velocity is 1.4035 m/s.
Then the inlet volume will be
As the diameter of tube is 130 mm, then the radius is 65 mm and inlet velocity is 1.4 m/s
So, the inlet volume is 0.019 m³/s.
Thus, the inlet velocity is 1.4 m/s and inlet volume is 0.019 m³/s.
Answer:
Explanation:
Mass of the cable car, m = 5800 kg
It goes 260 m up a hill, along a slope of
Therefore vertical elevation of the car =
Now, when you get into the cable car, it's velocity is zero, that is, initial kinetic energy is zero (since K.E. = ). Similarly as the car reaches the top, it halts and hence final kinetic energy is zero.
Therefore the only possible change in the cable car system is the change in it's gravitational potential energy.
Hence, total change in energy = mgh =
where, g = acceleration due to gravity
h = height/vertical elevation