The velocity of the aircraft relative to the ground is 240 km/h North
Explanation:
We can solve this problem by using vector addition. In fact, the velocity of the aircraft relative to the ground is the (vector) sum between the velocity of the aircraft relative to the air and the velocity of the air relative to the ground.
Mathematically:

where
v' is the velocity of the aircraft relative to the ground
v is the velocity of the aircraft relative to the air
is the velocity of the air relative to the ground.
Taking north as positive direction, we have:
v = +320 km/h
(since the air is moving from North)
Therefore, we find
(north)
Learn more about vector addition:
brainly.com/question/4945130
brainly.com/question/5892298
#LearnwithBrainly
Answer:

Since we have identical diodes we can use the equation:

And replacing we have:
Since we know that 1 mA is drawn away from the output then the real value for I would be

And for this case the value for
would be:

And the output votage on this case would be:

And the net change in the output voltage would be:

Explanation:
For this case we have the figure attached illustrating the problem
We know that the equation for the current in a diode id given by:
![I_D = I_s [e^{\frac{V_D}{V_T}} -1] \approx I_S e^{\frac{V_D}{V_T}}](https://tex.z-dn.net/?f=%20I_D%20%3D%20I_s%20%5Be%5E%7B%5Cfrac%7BV_D%7D%7BV_T%7D%7D%20-1%5D%20%5Capprox%20I_S%20e%5E%7B%5Cfrac%7BV_D%7D%7BV_T%7D%7D)
For this case the voltage across the 3 diode in series needs to be 2 V, and we can find the voltage on each diode
and each voltage is the same v for each diode, so then:

Since we have identical diodes we can use the equation:

And replacing we have:

Since we know that 1 mA is drawn away from the output then the real value for I would be

And for this case the value for
would be:

And the output votage on this case would be:

And the net change in the output voltage would be:

Lets make the original number of nuclides at the start is 100.
If 7/8 of 100 is decayed, that means 87.5 decayed.

And there is 1/8 left of the number of nuclide 100. Which is 12.5


How many Half lifes passed for 100 to become 12.5 is 3 Half-Lives.

Each Half-Life is 80 seconds so there is 240 seconds

The answer is that it takes 240 seconds.