a bobsled has a momentum of 1500 kg*m/s to the south. Air resistance reduces its momentum to 750 kg*m/s to the south. What impul
2 answers:
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Answer:
223 degree
Explanation:
We are given that
Magnitude of resultant vector= 8 units
Resultant vector makes an angle with positive -x in counter clockwise direction
We have to find the magnitude and angle of the equilibrium vector.
We know that equilibrium vector is equal in magnitude and in opposite direction to the given vector.
Therefore, magnitude of equilibrium vector=8 units
x-component of a vector=
Where v=Magnitude of vector
Using the formula
x-component of resultant vector=
y-component of resultant vector=
x-component of equilibrium vector=
y-component of equilibrium vector=
Because equilibrium vector lies in III quadrant
The angle lies in III quadrant
In III quadrant ,angle =
Angle of equilibrium vector measured from positive x in counter clock wise direction=180+43=223 degree
Explanation:
Below is an attachment containing the solution.
Answer:
28.1 mph
Explanation:
The force of friction acting on the car provides the centripetal force that keeps the car in circular motion around the curve, so we can write:
(1)
where
is the coefficient of friction
m is the mass of the car
g = 9.8 m/s^2 is the acceleration due to gravity
v is the maximum speed of the car
r is the radius of the trajectory
On the snowy day,
So the radius of the curve is
Now we can use this value and re-arrange again the eq. (1) to find the maximum speed of the car on a sunny day, when . We find: