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pshichka [43]
2 years ago
9

A projectile follows a straight-line path instead of a parabolic trajectory. Which could be the launch angle? would it be 90 or

45 or 3o??
Physics
2 answers:
Gnesinka [82]2 years ago
7 0
<em>projectile can only follow the straight line path when it is launched upward straightly so the correct option is <u>90 degree with respect to horizontal x -axis ..:)</u></em>
Alja [10]2 years ago
6 0

Answer:

90 degree

Explanation:

For the horizontal projection or the vertical projection, the path traversed by the projectile is a straight line .

So the angle of projection is 0 degree or 90 degree.

In this condition the motion is in one dimension. If the angle of projection is any arbitrary angle except 0 degree or 90 degree, the motion of the projectile is parabolic.

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4

Explanation:

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Bradley gets an x-ray at a radiology clinic that employs its own technologists and radiologists. Would the coder at the clinic r
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Answer:

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If Bradley examination was done and interpreted in the same facility, the radiologist code is used example- procedure code 72100- Radiologic examination, spine, lumbosacral, 2 or 3 views is reported.

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if Bradley’s x-ray were sent to an independent radiologist for interpretation, then the procedure code 76140 is used in reporting.

8 0
1 year ago
Maverick and goose are flying a training mission in their F-14. They are flying at an altitude of 1500 m and are traveling at 68
den301095 [7]

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The bomb will remain in air for <u>17.5 s</u> before hitting the ground.

Explanation:

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Initial vertical height is, y_0=1500\ m

Initial horizontal velocity is, u_x=688\ m/s

Initial vertical velocity is, u_y=0(\textrm{Horizontal velocity only initially)}

Let the time taken by the bomb to reach the ground be 't'.

So, consider the equation of motion of the bomb in the vertical direction.

The displacement of the bomb vertically is S=y-y_0=0-1500=-1500\ m

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Therefore, the displacement of the bomb is given as:

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6 0
2 years ago
Assume that the mass has been moving along its circular path for some time. You start timing its motion with a stopwatch when it
lesya692 [45]

Answer:

v = R\omega(-sin\omega t \hat i + cos\omega t \hat j)

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6 0
2 years ago
The loudness of a sound is inversely proportional to the square of your distance from the source of the sound. if your friend is
kirill [66]
Let loudness be L, distance be d, and k be the constant of variation such that the equation that would best represent the given above is,
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For Case 2,
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For k to be equal, L1 = 16L2. 
Therefore, the loudness at your friend's position is 16 times that of yours. 
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2 years ago
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