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2 years ago

The electric field inside a cell membrane is 8.0 MN/C. Part A What's the force on a singly charged ion in this field?

Physics

1 answer:

dlinn [17]2 years ago

7 0

Answer:

Force on the singly charged ion will be $12.6\times 10^{-13}N$

Explanation:

We have given electric field E = 8 MN/C

So electric field in N/C will be $E=8MN/C=8\times 10^6N/C$

It is given that ion so charge on ion will be equal to $e=1.6\times 10^{-19}C$

We have to find the electric force on the ion

Electric force is equal to $F=qE$ , here q is charge and E is electric field

So force on the charge will be equal to $F=8\times 10^6\times 1.6\times 10^{-19}=12.6\times 10^{-13}N$

So force on the singly charged ion will be $12.6\times 10^{-13}N$

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A(n) ________ has charge but negligible mass, whereas a(n) ________ has mass but no charge.

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Electron;Neutron is the correct answer.

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1 year ago

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Suppose an electrical wire is replaced with one having every linear dimension doubled (i.e., the length and radius have twice th

Flauer [41]

Answer:

The new resistance becomes half of the initial resistance.

Explanation:

The resistance of a wire is given by :

$R=\dfrac{\rho L}{A}$

$\rho$ = resistivity of material

L and A are linear dimension

If the electrical wire is replaced with one having every linear dimension doubled i.e. l' = 2l and r' = 2r

New resistance of wire is given by :

$R'=\dfrac{\rho L'}{A'}$

$R'=\dfrac{\rho (2L)}{\pi (2r)^2}$

$R'=\dfrac{1}{2}\dfrac{\rho L}{A}$

$R'=\dfrac{1}{2}R$

The new resistance becomes half of the initial resistance. Hence, this is the required solution.

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2 years ago

Koala bears can eat only certain kind of Australian eucalyptus leaves.koalas are considered

DaniilM [7]

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2 years ago

A baseball catcher puts on an exhibition by catching a 0.15-kg ball dropped from a helicopter at a height of 101 m. What is the

yaroslaw [1]

Answer:

The speed of the ball 1.0 m above the ground is 44 m/s (Answer A).

Explanation:

Hi there!

To solve this problem, let´s use the law of conservation of energy. Since there is no air resistance, the only energies that we should consider is the gravitational potential energy and the kinetic energy. Because of the conservation of energy, the loss of potential energy of the ball must be compensated by a gain in kinetic energy.

In this case, the potential energy is being converted into kinetic energy as the ball falls (this is only true when there are no dissipative forces, like air resistance, acting on the ball). Then, the loss of potential energy (PE) is equal to the increase in kinetic energy (KE):

We can express this mathematically as follows:

-ΔPE = ΔKE

-(final PE - initial PE) = final KE - initial KE

The equation of potential energy is the following:

PE = m · g · h

Where:

PE = potential energy.

m = mass of the ball.

g = acceleration due to gravity.

h = height.

The equation of kinetic energy is the following:

KE = 1/2 · m · v²

Where:

KE = kinetic energy.

m = mass of the ball.

v = velocity.

Then:

-(final PE - initial PE) = final KE - initial KE

-(m · g · hf - m · g · hi) = 1/2 · m · v² - 0 (initial KE = 0 because the ball starts from rest) (hf = final height, hi = initial height)

- m · g (hf - hi) = 1/2 · m · v²

2g (hi - hf) = v²

√(2g (hi - hf)) = v

Replacing with the given data:

√(2 · 9.8 m/s²(101 m - 1.0 m)) = v

v = 44 m/s

The speed of the ball 1.0 m above the ground is 44 m/s.

3 0

2 years ago

A solar heated house loses about 5.4 × 107 cal through its outer surfaces on a typical 24-h winter day.

mojhsa [17]

Answer:

Explanation:

Q=mcΔθ

Q=quantity of heat , m= mass of the storage rock

Δθ= temperature change.

m= Q/(cΔθ)

Q=5.4 $10^{7}$

Δθ=62°C-20°C

=42°C

c=0.21cal/g.°C

$m=\frac{5.4*10^{7} }{0.21*42} \\\\m=6122448.98g\\$

m≈6100000g

m≈6100kg

4 0

2 years ago