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Afina-wow [57]
2 years ago
15

Describing the motion of an object can be difficult to do and using graphs help make motion easier to understand. Motion is a ch

ange in position measured by distance and time. Speed tells us the rate at which an object moves. Speed graphs are distance-time graphs; sometimes people label them as position-time graphs as well. Time is plotted on the X-axis and distance or position on the Y-axis of a line graph.
A distance-time graph tells us how far an object has moved with time.
• The steeper the graph, the faster the motion.
• A horizontal line means the object is not changing its position. It is not moving, and it is at rest.
• A downward sloping line means the object is returning to the start.

Use the text and the graphs above to choose all of the correct answers concerning speed?

In both graphs, speed will be measured in meters/second.
In graph A, the object travelled a distance of 40 meters in 4 seconds
The total distance travelled by the object in graph B is greater than the object in graph A.
In graph B, the object is at rest for 5 seconds.
The object in graph B was moving at a greater speed than the object in graph A

Physics
2 answers:
olga_2 [115]2 years ago
7 0

In both graphs, speed will be measured in meters/second.

In graph A, the object travelled a distance of 40 meters in 4 seconds

In graph B, the object is at rest for 5 seconds.

These are the correct answers

rewona [7]2 years ago
4 0

Answer:

Explanation:

1. In both graphs, speed is measured in meters/ second. The time measured in seconds is plotted on the X-axis while the distance measured in meters is plotted on the Y-axis.

2. Looking at the graph, you could identify the distance of 40 meters on the Y-axis and trace it down to time at 4 seconds on the X-axis.

3. The total distance travelled by the object in graph A is greater than the total distance travelled by the object in graph B. Graph B has a total distance of 25 m while graph A has a total distance of 50 m.

4. In graph B, the object is at rest at 5 seconds. From 5 seconds, it maintained a horizontal line indicating that it was static.

5. Graph A was moving at a greater speed than Graph B. Graph A had a speed of 10 m/s while Graph B had a speed of 5 m/s.

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Newton's rings are visible when a planoconvex lens is placed on a flat glass surface. For a particular lens with an index of ref
blsea [12.9K]

Answer:

the new diameter of the third ring = 0.607 mm

Explanation:

Consider the radius of \\m ^{th}\\ bright ring when air is in between the lens and the plate ;

r = \sqrt {\frac{(2m+1)\lambda R}{2}}

Using the expression: r (n)= \sqrt {\frac{(2m+1)\lambda R}{2n}} for the radius of the  \\m ^{th}\\ bright ring since the liquid (water ) of the refractive index 'n' is now in between the lens and the plate;

where;

\\m ^{th}\\ = number of fringe

λ = wavelength

R = radius

n = refractive index of water

Now ;

r (n)=\frac {r}{n}}

the radius r of the third bright ring when the air is in between lens and plate = r= \frac{0.700 \ mm}{2} \\\\

r= 0.35 \ mm

The new radius of the third bright fringe is r(3) = \frac{0.35}{\sqrt 1.33}

r(3) = 0.3035 \ mm

Calculating the new diameter ; we have:

d(3) = 2(r(3))

d(3) = 2(0.3035)

d = 0.607 mm

Thus, the new diameter of the third ring = 0.607 mm

7 0
2 years ago
A simple arrangement by means of which e.m.f,s. are compared is known
strojnjashka [21]

Answer:

A simple arrangement by means of which e.m.f,s. are compared is known as?

(a)Voltmeter

(b)Potentiometer

(c)Ammeter

(d)None of the above

Explanation:

5 0
2 years ago
A hydraulic lift raises a 2000 kg automobile when a 500 N force is applied to the smaller piston. If the smaller piston has an a
Inga [223]

Answer:

The cross-sectional area of the larger piston is 392cm ^{2}[/tex]

Explanation:

To solve this problem we apply the following formula:

Pascal principle: F=P*A   Formula (1)

F=Force applied to the piston

P: Pressure

A= Piston area

Nomenclature:

Fp= Force on the primary piston= 500N

W= car weight =m*g=2000kg*9.8m/s2= 19600N

Fs= Force on the secondary piston= W = 19600N

Ap= Primary piston area=10cm^{2} =10*10^{-4}m^{2}

As= Secondary piston area=?

The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.

In the equation (1)

P=F/A

Pp=Ps

\frac{Fp}{Ap} = \frac{Fs}{As}

As= \frac{Fs*Ap}{Fp}

As=\frac{19600*10*10^{-4} }{500}

As=0.0392m^{2} =0.0392*10^{4}cm^{2}

As=392cm ^{2}

5 0
2 years ago
The Vehicle Assembly Building at the Kennedy Space Center in Florida has a volume of 3,666,500 m3. Convert this volume to liters
maksim [4K]
<h2>Volume of vehicle Assembly Building at the Kennedy Space Center in Florida = 3.67 x 10⁹ L</h2>

Explanation:

The Vehicle Assembly Building at the Kennedy Space Center in Florida has a volume of 3,666,500 m³.

Volume = 3,666,500 m³

1 m³ = 1000 L

So volume = 3,666,500 x 1000 = 3666500000 L

Volume of vehicle Assembly Building at the Kennedy Space Center in Florida = 3666500000 L

Volume of vehicle Assembly Building at the Kennedy Space Center in Florida = 3.67 x 10⁹ L

3 0
2 years ago
A cart starts from rest and accelerates at 4.0 m/s2 for 5.0 s, then maintains that velocity for 10 s, and then decelerates at th
zhannawk [14.2K]

Answer:

Final speed of car = 12 m/s

Explanation:

We have equation of motion v = u + at, where v is final velocity, u is initial velocity, a is acceleration and t is time.

a) A cart starts from rest and accelerates at 4.0 m/s² for 5.0 s

        v = ?

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        a = 4.0 m/s²

         t = 5 s

         v = u + at = 0 + 4 x 5 = 20 m/s

b) Then maintains that velocity for 10 s

        v = ?

        u = 20 m/s

        a = 0 m/s²

         t = 10 s

         v = u + at = 20 + 0 x 10 = 20 m/s

c) Then decelerates at the rate of 2.0 m/s² for 4.0 s

        v = ?

        u = 20 m/s

        a = -2.0 m/s²

         t = 4 s

         v = u + at = 20 + -2 x 4 = 12 m/s

Final speed of car = 12 m/s

3 0
2 years ago
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