Consider a horizontal layer of the dam wall of thickness dx located a distance x above the reservoir floor. What is the magnitud
e dF of the force on this layer that results from adding the water to the reservoir? Express your answer in terms of x, dx, the magnitude of the acceleration due to gravity g, and any quantities from the problem introduction.
1 answer:
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Answer:
fcosθ + Fbcosθ =Wtanθ
Explanation:
Consider the diagram shown in attachment
fx= fcosθ (fx: component of friction force in x-direction ; f: frictional force)
Fbx= Fbcosθ ( Fbx: component of braking force in x-direction ; Fb: braking force)
Wx= Wtanθ (Wx: component of weight in x-direction ; W: Weight of semi)
sum of x-direction forces = 0
fx+ Fbx=Wx
fcosθ + Fbcosθ =Wtanθ
Answer : Tension in the line = 936.7 N
Explanation :
It is given that,
Mass of student, m = 65 kg
The angle between slackline and horizontal,
The two forces that acts are :
(i) Tension
(ii) Weight
So, from the figure it is clear that :
Hence, this is the required solution.
