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pogonyaev
2 years ago
8

Moving company uses a machine to raise a 900 Newton refrigerator to the second floor of a building machine consists of a single

pulley with a mechanical advantage of 1 how many newtons of input force will it take to raise the refrigerator
Physics
2 answers:
Juliette [100K]2 years ago
6 0
Mechanical advantage of a machine is the ratio of the output force over the input force or M=Fo/Fi. Since M=1, Fi=Fo, or the input force is equal to the output force. This means that to raise the refrigerator that weighs 900 N, we need the same input force of 900 N, or Fo=Fi=900 N. 
Scorpion4ik [409]2 years ago
4 0

Answer: 900 n

Explanation:

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Three cars (car F, car G, and car H) are moving with the same velocity when the driver suddenly slams on the brakes, locking the
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Answer:

The car F.

Explanation:

Because, the longer skid occurs with greater inertia. Objects with more mass produces more inertia.

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Military specifications often call for electronic devices to be able to withstand accelerations of 10 g. to make sure that their
trapecia [35]
The solution for this problem is:
(10 x 9.8) = 98.1 m/sec^2 acceleration. Time, to travel 9.4cm or (.094m.), at acceleration of 98m/sec^2

= sqrt(2d/a), = sqrt (98.1 m/sec^2/0.094m) = 32.3050619 sec per cycle

Frequency = (w/2pi), = 32.3050619/2pi
= 32.3050619/6.28318531
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6 0
2 years ago
Three particles are moving perpendicular to a uniform magnetic field and travel on circular paths (see the drawing). They have t
Vaselesa [24]

Explanation:

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r=mv / Bq

= k/ q

where   k   =   m v / B         is a constant.

i.e.   more is the magnitude of  charge, less is the radius. (inversely proportional)

From the diagram  r_3   >   r_2   >   r_1  (more the curvature, less is the radius)

( although drawing is not given i am assuming the above order, however, one can change the order as per the diagram. The concept used remains the same)

therefore,    q_1   >   q_2   >   q_3 .

7 0
2 years ago
The mass per unit length of a 14-gauge copper wire is 18.5 g/m. If the wire is placed running along the horizontal x-axis (east-
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0.6295 A

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2 years ago
A cylindrical wire has a resistance R and resistivity ρ. If its length and diameter are BOTH cut in half, what will be its resis
snow_lady [41]

Answer:

The resistance will be 2×R

Explanation:

We note that the resistivity of a cylindrical wire is given by the following relation;

\rho = \frac{RA}{L}

Where:

ρ = Resistivity of the wire

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A = Cross sectional area of the wire = π·D²/4

L = Length  of the wire

Rearranging, we have;

R= \frac{\rho L}{A}

If the length and the diameter are both cut in half, we have;

L₂ = L/2

A₂ =π·D₂²/4 = \pi \cdot \left (\frac{D}{2}   \right )^{2} \times \frac{1}{4}  = \pi \cdot \frac{D^{2}}{16} = A/4

Therefore, the new resistance, R₂ can be expressed as follows;

R_2= \frac{\rho \frac{L}{2} }{\frac{A}{4} } = \rho \frac{L}{2} \times \frac{4}{A} = 2 \times  \frac{\rho L}{A}

Hence, the new resistance R₂ =  2×R, that is the resistance will be doubled.

8 0
2 years ago
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