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elena-s [515]
2 years ago
8

The first law of thermodynamics states that ___. when a process converts energy from one form to another, some energy converted

into heat, an unusable form of energy energy can neither be created nor destroyed, but it can change from one form to another energy flows through ecosystems without being recycled most energy in ecosystems comes from the Sun
Physics
2 answers:
barxatty [35]2 years ago
7 0

The first law of thermodynamics states that energy cannot be created or destroyed, but it can change from one form to another

ratelena [41]2 years ago
5 0

The answer is: energy cannot be created or destroyed under normal conditions

The first law of thermodynamics was introduced by  Rudolf Clausius and  William Rankine in the year of 1950s. It stated that The energy cannot be destroyed or created, but it can be changed/altered. 'Normal' conditions in this context refers to the condition where the energy is not being intervened by external factors in any way.

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An alpha particle is identical to a(n) _____.
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Helium atom,  in other words, it consistis of a particle having four protons and two neutrons.
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Wrapping paper is being unwrapped from a 5.0-cm radius tube, free to rotate on its axis. if it is pulled at the constant rate of
lisov135 [29]
So the equation for angular velocity is

Omega = 2(3.14)/T

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In order to find T, the tangential velocity is

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5 0
2 years ago
A uniform metre rule of weight 0.9 N is suspended horizontally by two vertical loops of thread A and B placed at 20cm and 30cm f
podryga [215]

Answer:

(a) 29 cm

(b) 43.5 cm

Explanation:

(a) when loop A is slack, there are three forces acting on the metre rule.

-0.9 N at 50 cm mark

T at 70 cm mark

-2 N at x

Taking the sum of the torques about B:

∑τ = Iα

(-0.9 N) (50 cm − 70 cm) + (-2 N) (x − 70 cm) = 0

18 Ncm − 2 N (x − 70 cm) = 0

2 N (x − 70 cm) = 18 Ncm

x − 70 cm = 9 cm

x = 79 cm

The distance from the center is |50 cm − 79 cm| = 29 cm.

(b) when loop B is slack, there are three forces acting on the metre rule.

-0.9 N at 50 cm mark

T at 20 cm mark

-2 N at x

Taking the sum of the torques about A:

∑τ = Iα

(-0.9 N) (50 cm − 20 cm) + (-2 N) (x − 20 cm) = 0

-27 Ncm − 2 N (x − 20 cm) = 0

2 N (x − 20 cm) = -27 Ncm

x − 20 cm = -13.5 cm

x = 6.5 cm

The distance from the center is |50 cm − 6.5 cm| = 43.5 cm

3 0
2 years ago
To determine the y-component of a projectile’s velocity, what operation is performed on the angle of the launch?
koban [17]

<em>To determine the y component of velocity of a projectile </em><u><em>sine </em></u><em>operation is performed on the angle of launch.</em>

<u>Answer:</u> <em>sine</em>

<u>Explanation:</u>

Thus a_x=0,a_y=g

The initial velocity u can be resolved along two directions.

Along the X direction initial velocity = u cos θ

Along y direction initial velocity= u sin θ

From the equation of motion v= u+at

Thus velocity along x direction v_x=u cos θ

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3 0
2 years ago
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Which diagram shows how Rachel can see a candle flame?
SIZIF [17.4K]

Answer:

C

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