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Irina18 [472]
2 years ago
13

Wrapping paper is being unwrapped from a 5.0-cm radius tube, free to rotate on its axis. if it is pulled at the constant rate of

10 cm/s and does not slip on the tube, the angular velocity of the tube is:
Physics
1 answer:
lisov135 [29]2 years ago
5 0
So the equation for angular velocity is

Omega = 2(3.14)/T

Where T is the total period in which the cylinder completes one revolution.

In order to find T, the tangential velocity is

V = 2(3.14)r/T

When calculated, I got V = 3.14

When you enter that into the angular velocity equation, you should get 2m/s
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Go to the roller coaster simulation and click on the "launch" button. Pay attention to the pie chart as the roller coaster moves
Paladinen [302]

Answer:

The kinetic energy INCREASES as the roller coaster goes downhill.

Kinetic energy is greatest at POINT 2

Potential energy is greatest at POINT 1

Kinetic energy is decreasing while potential energy is increasing between points 3 AND 4

Which chart comes closest to the relationship between kinetic energy and potential energy at point 6 - CHART OF ANY POINT IN THE SAME HEIGHT AS OF 6

Explanation:

⇒As the potential energy increases , kinetic energy decreases.

⇒Potential energy here is gravitational potential energy.

⇒Thus, more we move away from the centre of the earth , more will be the gravitational potential energy or decrease in kinetic energy

3 0
2 years ago
Read 2 more answers
Rock X is released from rest at the top of a cliff that is on Earth. A short time later, Rock Y is released from rest from the s
frosja888 [35]

Answer:

C) True. S increases with time, v₁ = gt and v₂ = g (t-t₀)  we see that for the same t v₁> v₂

Explanation:

You have several statements and we must select which ones are correct. The best way to do this is to raise the problem.

Let's use the vertical launch equation. The positive sign because they indicate that the felt downward is taken as an opponent.

Stone 1

    y₁ = v₀₁ t + ½ g t²

    y₁ = 0 + ½ g t²

Rock2

It comes out a little later, let's say a second later, we can use the same stopwatch

     t ’= (t-t₀)

    y₂ = v₀₂ t ’+ ½ g t’²

    y₂ = 0 + ½ g (t-t₀)²

    y₂ = + ½ g (t-t₀)²

Let's calculate the distance between the two rocks, it should be clear that this equation is valid only for t> = to

    S = y₁ -y₂

    S = ½ g t²– ½ g (t-t₀)²

    S = ½ g [t² - (t²- 2 t to + to²)]  

    S = ½ g (2 t t₀ - t₀²)

    S = ½ g t₀ (2 t -t₀)

This is the separation of the two bodies as time passes, the amount outside the Parentheses is constant.

For t <to.  The rock y has not left and the distance increases

For t> = to.  the ratio (2t/to-1)> 1 therefore the distance increases as time

passes

Now we can analyze the different statements

A) false. The difference in height increases over time

B) False S increases

C) Certain s increases with time, v₁ = gt and V₂ = g (t-t₀) we see that for the same t   v₁> v₂

3 0
2 years ago
The energy transfer diagram shows energy transfer in an MP3 player. Useful energy is transferred away from the MP3 player by lig
OLEGan [10]

Answer:

heat and sound.

Explanation:

Though some would argue that the heat is not useful. I guess it depends on if your hands are cold.

4 0
2 years ago
 If the gauge pressure of a gas is 114 kPa, what is the absolute pressure?
Anastasy [175]

Answer:

D. 214 kPa

Explanation:

The absolute pressure is given by:

p = p_a + p_g

where

p is the absolute pressure

p_a \sim 100 kPa is the atmospheric pressure

p_g is the gauge pressure

In this problem, we have

p_g = 114 kPa

So, the atmospheric pressure is

p = 100 kPa + 114 kPa = 214 kPa

4 0
2 years ago
Read 2 more answers
Why is the transverse spatial extent of a photon proportional to its wavelength which is a longitudinal quantity?
otez555 [7]
In quantum mechanics, particularly the wave-particle theory, it states that light behaves like a wave or a particle. For the wave behavior, its movement is measured in wavelengths while the time for each wavelength is the frequency. For the particle behavior, according to Planck, the energy of the photon (light particle) is determined as

E = hc/wavelength, where h is the Planck's constant (<span>6.626 x 10-34 J-s per particle) and c is the speed of light ( 3 x 10^8m/s)

As you can see, the energy of the photon is INVERSELY PROPORTIONAL to the wavelength with the Planck's constant as the constant of proportionality.</span>
7 0
2 years ago
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