At a certain instant after jumping from the airplane A, a skydiver B is in the position shown and has reached a terminal (consta
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Answer:
The energy of the system is 15 J.
Explanation:
Given that,
Energy E = 2.5 J
Amplitude = 10 cm
We need to calculate the spring constant
Using formula of mechanical energy of the system
Put the value into the formula
If the block is replaced by a block with twice the mass of the original block
Amplitude = 6 cm
We need to calculate the energy
Using formula of mechanical energy
Put the value into the formula
Hence, The energy of the system is 15 J.
Initially, the energies are:
At final point, the energies are:
Using conservation law of energy,
The equation is further simplified as:
Explanation:
It is given that,
Area of square coil,
Side of the square, L = 0.02 m
Number of turns, N = 10000
Uniform magnetic field, B = 1.5 T
Speed, v = 100 m/s
An emf is induced in the coil which is given by :
E = 30000 V
Breakdown voltage of air,
Let d is the gap between the two wires connected to the ends of the coil and still get a spark. So,
Electric field,
d = 0.075 m
Hence, this is the required solution.