Answer:
See explanation below
Explanation:
As I say in the comments, the question is incomplete, however, I will try to answer this by using data that I found on another site.
This is the part of the question that is not here:
If measurements are recorded to the nearest
tenth of a kilogram, find the fraction of these poodles
with weights
(a) over 9.5 kilograms;
(b) of at most 8.6 kilograms;
So, assuming a mean of 8 kg, and 0.9 of standard deviation, let X represents the weight of the poodles
The expression to calculate the fraction of poodle needed is:
Z = X - u / d
u: weight of the large number of poodle
d: standard deviation
Replacing data of a) wer have:
Z = 9.5 - 8 / 0.9
Z = 1.67
With this value, we need to take the value of Z, and see the area under the curve of standard deviation (see table attached)
Therefore:
P (X > 9.5) = P(Z > 1.67) = 0.5 - P (Z < 1.67) = 0.5 - 0.4525 = 0.0475
b) In this part, is the same as part a) so:
Z = 8.6 - 8 / 0.9 = 0.67
The value for area in the curve is 0.2486 so:
P = 0.5 + 0.2486 = 0.7486
Hope this helps
