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9966 [12]
2 years ago
14

Complete the statements using data from Table A of your Student Guide. The speed of the cart after 8 seconds of Low fan speed is

cm/s. The speed of the cart after 3 seconds of Medium fan speed is cm/s. The speed of the cart after 6 seconds of High fan speed is cm/s.
Physics
2 answers:
Colt1911 [192]2 years ago
8 2

Answer:

The speed of the cart after 3 seconds of Low fan speed is 54.0 cm/s

The speed of the cart after 5 seconds of Medium fan speed is 120.0 cm/s

The speed of the cart after 2 seconds of High fan speed is 64.0 cm/s

Explanation:

just did it on edge

finlep [7]2 years ago
4 0

Answer:

The speed of the cart after 8 seconds of Low fan speed is  72.0 cm/s

The speed of the cart after 3 seconds of Medium fan speed is   36.0 cm/s

The speed of the cart after 6 seconds of High fan speed is  96.0 cm/s

Explanation:

took the test on edgenuity

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Frances drew a diagram to show electromagnetic induction.
kari74 [83]

Answer:

The answer is B) Magnetic field

Explanation:

I chose it and I got it right

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2 years ago
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Because the soles of your shoes have cleats, you can exert a forward force of 100 N even on slippery ice. A 10-kg picnic cooler
Brilliant_brown [7]

Answer:

you must throw 3 snowballs

Explanation:

We can solve this exercise using the concepts of conservation of the moment, let's define the system as formed by the refrigerator and all the snowballs. Let's write the moment

Initial. Before bumping that refrigerator

          p₀ = n m v₀

Where n is the snowball number

Final. When the refrigerator moves

         pf = (n m + M) v

The moment is preserved because the forces during the crash are internal

        n m v₀ = (n m + M) v

        n m (v₀ - v) = M v

        n = M/m    v/(vo-v)

Let's look for the initial velocity of the balls, suppose the person throws them with the maximum force if it slides in the snow (F = 100N), let's use the second law and Newton

          F = m a

          a = F / m

The distance the ball travels from zero speed to maximum speed is the extension of the arm (x = 1 m), let's look kinematically for the speed of the balls when leaving the arm

          v₁² = v₀² + 2 a x

          v₁² = 0+ 2 (100/1) 1

          v₁ = 14.14 m / s

This is the initial speed for the crash

         v₀ = v = 14.14 m / s

  Let's calculate

           n = M/m   v/ (v₀-v)

           n = 10/1   3 / (14.14 -3)

          n = 2.7 balls

you must throw 3 snowballs

7 0
2 years ago
A cylindrical specimen of brass that has a diameter listed above, a tensile modulus of 110 GPa, and a Poisson's ratio of 0.35 is
Irina-Kira [14]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The strain experienced by the specimen is 0.00116 which is option A

Explanation:

The explanation is shown on the second uploaded image

8 0
2 years ago
If you peel two strips of transparent tape off the same roll and immediately let them hang near each other, they will repel each
g100num [7]

Answer:

1.

Firstly removing off one strip and it leaves electrons behind, so the strip becomes positively charged.

2. The roll however is not negatively charged because it is "earthed " by the hand holding it, thus excess negatives repel each other away through the hand.

3.Tearing off the next strip and once more it leaves electrons behind, the new strip is also positively charged and will repel the first strip.

4. Then, tear two strips apart and one will leave electrons behind on the other. Meaning that one strip is positive and the other is negative and they will attract each other.

5 0
2 years ago
Water, of density 1000 kg/m3, is flowing in a drainage channel of rectangular cross-section. The width of the channel is 15 m, t
Rom4ik [11]

Answer:

Water flowing rate=  (300000kg/s) = (300000l/s)

Explanation:

First with the section of the channel, the depth of the water and the speed of the fluid we can determine the volume of fluid that circulates per second through the channel:

Volume per time= 15m × 8m × (2.5m/s)= 300 m³/s

With this volume of circulating fluid per second elapsed, we multiply it by the density of the water to determine the kilograms or liters of water that circulate through the channel per second elapsed:

Water flowing rate= (300m³/s) × (1000kg/m³)= (300000kg/s) = (300000l/s)

Taking into account that 1kg of water is approximately equal to 1 liter of water.

8 0
2 years ago
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