Sasha is correct: No, the velocity is changing at the top so the acceleration cant be zero.
Explanation:
The acceleration of an object is equal to the rate of change in velocity of the object:
(1)
where
is the change in velocity
is the time interval
For the cart on the ramp, as the cart reaches the top of the ramp, its velocity becomes temporarily zero:
v = 0
This is the origin of Malia's mistake.
However, this only lasts a moment; in reality, its velocity is changing, in particular its direction is changing (from upward to downward).
As we can see from eq.(1), a non-zero change in velocity implies a non-zero acceleration. Therefore, Sasha is right, since the cart has a non-zero acceleration.
Learn more about acceleration:
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Explanation:
The given data is as follows.
Mass of small bucket (m) = 4 kg
Mass of big bucket (M) = 12 kg
Initial velocity () = 0 m/s
Final velocity () = ?
Height = 2 m
and, = 0 m
Now, according to the law of conservation of energy
starting conditions = final conditions
235.44 = + 78.48
= 4.43 m/s
Thus, we can conclude that the speed with which this bucket strikes the floor is 4.43 m/s.
Answer:
The maximum speed of the car at the bottom of that drop is 26.34 m/s.
Explanation:
Given that,
The maximum vertical distance covered by the roller coaster, h = 35.4 m
We need to find the maximum speed of the car at the bottom of that drop. It is a case of conservation of energy. The energy at bottom is equal to the energy at top such that :
v = 26.34 m/s
So, the maximum speed of the car at the bottom of that drop is 26.34 m/s. Hence, this is the required solution.
Answer:
The freight train would take 542.265 second to increase the speed of the train from rest to 80.0 kilometers per hour.
Explanation:
Statement is incomplete. Complete description is presented below:
<em>A freight train has a mass of </em><em>. The wheels of the locomotive push back on the tracks with a constant net force of </em>
<em>, so the tracks push forward on the locomotive with a force of the same magnitude. Ignore aerodynamics and friction on the other wheels of the train. How long, in seconds, would it take to increase the speed of the train from rest to 80.0 kilometers per hour?</em>
If locomotive have a constant net force (), measured in newtons, then acceleration (
), measured in meters per square second, must be constant and can be found by the following expression:
(1)
Where is the mass of the freight train, measured in kilograms.
If we know that and
, then the acceleration experimented by the train is:
Now, the time taken to accelerate the freight train from rest (), measured in seconds, is determined by the following formula:
(2)
Where:
- Final speed of the train, measured in meters per second.
- Initial speed of the train, measured in meters per second.
If we know that ,
and
, the time taken by the freight train is:
The freight train would take 542.265 second to increase the speed of the train from rest to 80.0 kilometers per hour.
Answer:
Column X. Tangential Speed
Column Y. radius
Explanation:
The equation for centripetal acceleration is
= v² / r
Where v is the tangential velocity of the body and the radius of curvature.
To analyze this equation you must place the tangential velocity in one column and in the other the turning radius
Let's check the answers
Column X. Tangential Speed
Column Y. radius
This is the correct answer.