B
Think of inertia of getting into a car accident without a seat belt although the car stops you will not you would likely fly out the window
Answer:
The displacement of the spring due to weight is 0.043 m
Explanation:
Given :
Mass
Kg
Spring constant 
According to the hooke's law,

Where
force,
displacement
Here,
(
)
N
Now for finding displacement,

Here minus sign only represent the direction so we take magnitude of it.

m
Therefore, the displacement of the spring due to weight is 0.043 m
A = horizontal displacement of the humming bird = 1.2 m
B = vertical displacement of the humming bird = 1.4 m
C = net displacement of the humming bird from initial to final position = ?
In the triangle drawn , Using Pythagorean theorem
C = √(A² + B²)
inserting the values
C = √(1.2² + 1.4²)
C = √(1.44 + 1.96)
C = √(3.4)
C = 1.4 m
Hence the net displacement of hummingbird comes out to be 1.4 m
1110 atm
Let's start by calculating how many cm deep is 36,000 feet.
36000 ft * 12 in/ft * 2.54 cm/in = 1097280 cm
Now calculate how much a column of water 1 cm square and that tall would mass.
1097280 cm * 1.04 g/cm^3 = 1141171.2 g/cm^2
We now have a number using g/cm^2 as it's unit and we desire a unit of Pascals ( kg/(m*s^2) ).
It's pretty obvious how to convert from g to kg. But going from cm^2 to m is problematical. Additionally, the s^2 value is also a problem since nothing in the value has seconds as an unit. This indicates that a value has been omitted. We need something with a s^2 term and an additional length term. And what pops into mind is gravitational acceleration which is m/s^2. So let's multiply that in after getting that cm^2 term into m^2 and the g term into kg.
1141171.2 g/cm^2 / 1000 g/kg * 100 cm/m * 100 cm/m = 11411712 kg/m^2
11411712 kg/m^2 * 9.8 m/s^2 = 111834777.6 kg/(m*s^2) = 111834777.6 Pascals
Now to convert to atm
111834777.6 Pa / 1.01x10^5 Pa/atm = 1107.2750 atm
Now we gotta add in the 1 atm that the atmosphere actually provides (but if you look closely, you'll realize that it won't affect the final result).
1107.274 atm + 1 atm = 1108.274 atm
And finally, round to 3 significant figures since that's the accuracy of our data, giving 1110 atm.
Answer:
I) 57.5 m
Il) 50 m/s
Explanation:
Given that a boy stands at a certain distance from a large building and blows a whistle.
After 2.3s he hears the echo of the sound. The speed V of the sound will be:
V = 2X / T
Where X is the distance covered
V = 2X / 2.3
V = 0.87X ...... (1)
He moves 50m towards the building and blows his whistle again; this time the echo reaches him after 2.0s.
V = (2×50) / 2
V = 50 m/s
Substitutes the V into equation 1
50 = 0.87X
X = 50 / 0.87
57.5 m
Therefore, the Boys original distance from the building is 57.5m and the
Speed of sound in air is 50m/s