Answer:

Explanation:
given data:
wavelength \lambda = 708nm = 708*10^{-9} m
using the following relation:

according to the given information
second and third dark fringe is at same location. so






Answer:
The impact force will be same for both the cases.
Explanation:
The rate of change of momentum is known as the Impulse and is given by:

where
I = Impulse


Now,
In first case both the cars are identical and have same velocity and in the second case, the wall is stationary.
Also, in both the cases the car does not bounces off the things it hit.
Thus

Thus
Impact force, 
Therefore, impact force is same for both the cases.
Summary:
a= 12.0 m/(s^2)
v= 100m/s
t1= 2.0s => s1=?
t2=5.0s => s2=?
t3=10.0s => s3=?
——————
Solution:
• when t1=2.0 s, I have gone:
S1= v*t1 + 1/2*a*(t1^2)
=100.0 *2 + 1/2*12.0*(2.0^2)
=224 (m)
• when t2=5.0s, I have gone
S2=v*t2+ 1/2*a*(t2^2)
= 100*5.0+ 1/2*12.0*(5.0^2)
=650 (m)
•when t3= 10.0s, I have gone:
S3=v*t3+ 1/2*a*(t3^2)
=100*10.0+ 1/2*12*(10.0^2)
=1600 (m)
Answer: a= ff+fh/m
Explanation: bc khan academy said it was d. a=ff +fh/m