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Minchanka [31]
1 year ago
14

Megan left her bicycle outside on the patio while she went on vacation for several weeks. When she returned, Megan discovered a

reddish substance, rust, on the handlebars of her bicycle. The rust is an example of a(n) __________.
Physics
2 answers:
Effectus [21]1 year ago
8 0
Rust is a chemical change. Chemical changes are when the substances that make up an object change into other chemicals. For example, rust. What happens is metal and oxygen/water react and create rust. Hope this helps :) 
Licemer1 [7]1 year ago
8 0

Answer:

The answer is Rust is and example of a chemical compound

Explanation:

Rust (Oxide) is a reddish layer that forms on the surface of iron and other metals because of oxidation caused by moisture or water. Oxide is an inorganic compound that is formed by joining some chemical element with oxygen, that is, an oxide is a chemical compound, formed by at least one oxygen atom and one atom of some other element.

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A harmonic wave travels in the positive x direction at 6 m/s along a taught string. A fixed point on the string oscillates as a
Lapatulllka [165]

Answer:

Amplitude, A = 0.049 meters

Explanation:

Given that,

A harmonic wave travels in the positive x direction at 6 m/s along a taught string. A fixed point on the string oscillates as a function of time according to the equation :

y = 0.049 \cos(7t) .......(1)

The general equation of a wave is given by :

y=A\cos(\omega t) .......(2)

A is amplitude of wave

On comparing equation (1) and (2) we get :

A = 0.049 meters

So, the amplitude of the wave is 0.049 meters.

3 0
2 years ago
Calculate the energy in the form of heat (in kJ) required to change 75.0 g of liquid water at 27.0 °C to ice at –20.0 °C. Assume
REY [17]

Explanation:

The given data is as follows.

          mass, m = 75 g

      T_{1} = 0^{o}C

      T_{2} = 27^{o}C

      Specific heat of water = 4.18

First, we will calculate the heat required for water is as follows.

            q = m C \times (T_{1} - T_{2})

               = 75 g \times 4.18 J/g^{o}C \times (0 - 27)^{o}C

               = 8464.5 J/mol

               = 8.46 kJ ......... (1)

Also, it is given that T_{3} = -20^{o}C = (20 + 273) K = 293 K and specific heat of ice is 2.108 kJ/kg K.

Now, we will calculate the heat of fusion as follows.

        q = mC \times (T_{3} - T_{1})

           = 0.075 kg \times 2.108 kJ/kg K \times (-293 - 0) K

           = -46.32 kJ ......... (2)

Now, adding both equations (1) and (2) as follows.

               8.46 kJ - 46.32 kJ

             = -37.86 kJ

Therefore, we can conclude that energy in the form of heat (in kJ) required to change 75.0 g of liquid water at 27.0^{o}C to ice at -20.0^{o}C is -37.86 kJ.

4 0
2 years ago
A 6000 kg lorry is reversing into a parking space at a speed of 0.5 m/s but collides with a car. The crumple zone of the car sto
zysi [14]

Answer:

3000 kg.m/s

Explanation:

Momentum, p is a product of mass and velocity hence

p=mv where m is mass and v is velocity.

Change in momentum is given by m(v_f-v_i) where subscripts f and i represent final and initial respectively. Since the lorry finally comes to rest then the final velocity is zero. Substituting the given figures then

Change in momentum= 6000(0-0.5)=-3000 kg.m/s

7 0
2 years ago
A thin, horizontal, 18-cm-diameter copper plate is charged to -3.8 nC. Assume that the electrons are uniformly distributed on th
son4ous [18]

Answer:

Part a)

E = 8436.7 N/C

Part b)

E = 8436.7 N/C

Explanation:

Part a)

Electric field due to large sheet is given as

E = \frac{\sigma}{2\epsilon_0}

\sigma = \frac{Q}{A}

Q = -3.8 nC

A = \pi(0.09)^2

A = 0.025 m^2

\sigma = \frac{-3.8\times 10^{-9}}{0.025}

\sigma = -1.5 \times 10^{-7} C/m^2

now the electric field is given as

E = \frac{-1.5 \times 10^{-7}}{2(8.85 \times 10^{-12})}

E = 8436.7 N/C

Part b)

Now since the electric field is required at same distance on other side

so the field will remain same on other side of the plate

E = 8436.7 N/C

5 0
2 years ago
The study of alternating electric current requires the solutions of equations of the form i equals Upper I Subscript max Baselin
KiRa [710]

Answer:

Explanation:

i = Imax sin2πft

given i = 180 , Imax = 200 , f = 50  , t = ?

Put the give values in the equation above

180 = 200 sin 2πft

sin 2πft = .9

sin2π x 50t = .9

sin 360 x 50 t = sin ( 360n + 64 )

360 x 50 t = 360n + 64

360 x 50 t =  64 ,  ( putting n = 0 for least value of t )

18000 t = 64

t = 3.55 ms  .

8 0
2 years ago
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