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2 years ago

14

Bears eat fruits such as berries and animals such as fish. They hibernate in the winter. They give birth to live young . Which o

f these terms apply to bears?

1 answer:

bulgar [2K]2 years ago

7 0

Answer:

Bears are consumers

Explanation:

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A 20 watt lightbulb uses 20 Joules of energy every second.A person expends 50 watts of energy per stair when climbing up stairs.

Pachacha [2.7K]

20W = 20 J/s

Energy expended during climbing stairs = 50 W of energy/stair = 50J/stair

For 20 stairs, Total energy = 50x20 = 1000 J

This can light bulbs for, T= 1000J/20 J/s =50 seconds

6 0

2 years ago

An owl has a mass of 4.00 kg. It dives to catch a mouse, losing 800.00 J of its GPE. What was the starting height of the owl, in

vesna_86 [32]

Answer:

height =20m

Explanation:

gpe=mgh

800=4×10×x

40x=800

x=20

3 0

2 years ago

Two convex thin lenses with focal lengths 10.0 cm and 20.0 cm are aligned on a common axis, running left to right, the 10-cm len

love history [14]

Answer:

(c) +6.67

Explanation:

f1 = 10 cm

f2 = 20 cm

u = Object distance = 15 cm

Distance between lenses = 20 cm

For first lens image distance

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{10}-\frac{1}{15}\\\Rightarrow \frac{1}{v}=\frac{1}{30}\\\Rightarrow v=30\ cm$

Distance from second lens is 10 cm to the right

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{20}-\frac{1}{-10}\\\Rightarrow \frac{1}{v}=\frac{3}{20}\\\Rightarrow v=6.67\ cm$

The final image will appear as +6.67 cm

3 0

2 years ago

Which diagram shows how Rachel can see a candle flame?

SIZIF [17.4K]

Answer:

C

Explanation:

If the arrows represent light rays, then Rachel sees a candle flame when the light released by the flame is received by her eyes.

5 0

2 years ago

A uniform metal bar is 5.00 m long and has mass 0.300 kg. The bar is pivoted on a narrow support that is 2.00 m from the left-ha

Firlakuza [10]

Explanation and answer:

This type of question can be clarified and sometimes solved by drawing a proper diagram or sketch. (see below)

Solution:

Since we do not know the reaction of the support, we can take moments about the support (thereby eliminating its involvement).

CCW moment = 0.900(5.00/2 - x) kg-m

CW moment = 0.300*(5.00/2-2.00)) = 0.150 kg-m

At equilibrium, CCW moment = CW moment, so

0.900(2.50-x) = 0.150

Expand and solve

2.25 - 0.900x = 0.150

0.900x = 2.25-0.15 = 2.10

x = 2.10 / 0.900 = 2.33 m (to nearest cm)

8 0

2 years ago