A girl and boy pull in opposite directions on a stuffed animal. The girl exerts a force of 3.5 N. The mass of the stuffed animal
2 answers:
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Answer:
the direction that should be walked by Ricardo to go directly to Jane is 23.52 m, 24° east of south
Explanation:
given information:
Ricardo walks 27.0 m in a direction 60.0 ∘ west of north, thus
A= 27
Ax = 27 sin 60 = - 23.4
Ay = 27 cos 60 = 13.5
Jane walks 16.0 m in a direction 30.0 ∘ south of west, so
B = 16
Bx = 16 cos 30 = -13.9
By = 16 sin 30 = -8
the direction that should be walked by Ricardo to go directly to Jane
R = √A²+B² - (2ABcos60)
= √27²+16² - (2(27)(16)(cos 60))
= 23.52 m
now we can use the sines law to find the angle
tan θ =
= By - Ay/Bx -Ax
= (-8 - 13.5)/(-13.9 - (-23.4))
θ = 90 - (-8 - 13.5)/(-13.9 - (-23.4))
= 24° east of south
Answer:
g = 0.905 gE
W = 67.9 N
Explanation:
given data
mass of Venus mv = 81.5% = 0.815
radius Rv = 94.9% = 0.949
weighs W = 75.0 N
solution
we apply here acceleration due to gravity at earth surface that is
g = = 9.80 m/s² ............1
so
g =
g = 0.905 gE
and
W = m gv
W = 0.905 m gE
W = 0.905 × 75
W = 67.9 N