Answer:
The impulse is 
The opponents velocity is 
The opponents head recoils velocity 
Explanation:
From the question we are told that
The force of the blow is 
The duration of the blow is 
The mass of the opponent is 
The mass of the opponents head is 
The impulse the boxer imparts is mathematically represented as
substituting values
The impulse can also be mathematically evaluated as
substituting values
The recoil velocity is mathematically represented as
substituting values
Answer:
Explanation:
Given that,
Mass of a toy, m = 0.62 kg
Horizontal force, F = 16.3 N
Force on the opposite direction, F' = 15.8 N
We need to find the acceleration of the toy.
Here, two forces are acting in opposite direction, the net force will be the difference of forces.
Net force = 16.3 N-15.8 N
=0.5 N
The formula for net force is given by :
F = ma
a is the acceleration of the toy
So, the acceleration of the toy is 
.
For this problem, we use the conservation of momentum as a solution. Since momentum is mass times velocity, then,
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
where
v₁ and v₂ are initial velocities of cart A and B, respectively
v₁' and v₂' are final velocities of cart A and B, respectively
m₁ and m₂ are masses of cart A and B, respectively
(7 kg)(0 m/s) + (3 kg)(0 m/s) = (7 kg)(v₁') + (3 kg)(6 m/s)
Solving for v₁',
v₁' = -2.57 m/s
<em>Therefore, the speed of cart A is at 2.57 m/s at the direction opposite of cart B.</em>
Hi!
Mechanical advantage is defined as the<em> ratio of force produced by an object to the force that is applied to it.</em>
In our case, this would be the ratio of the force applied by the claw hammer on the nail to the force Joel applies to the claw hammer, which is
160:40 or 4:1
So the mechanical advantage of the hammer is four.
Hope this helps!
The first law of thermodynamics says that the variation of internal energy of a system is given by:
where Q is the heat delivered by the system, while W is the work done on the system.
We must be careful with the signs here. The sign convention generally used is:
Q positive = Q absorbed by the system
Q negative = Q delivered by the system
W positive = W done on the system
W negative = W done by the system
So, in our problem, the heat is negative because it is releaed by the system:
Q=-1275 J
while the work is positive because it is performed by the surrounding on the system:
W=+855 J
So, the variation of internal energy of the system is
