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2 years ago

What is the most power in watts the ear can receive before the listener feels pain?

Physics

1 answer:

svp [43]2 years ago

5 0

The softest sound a human ear can hear is at 0dB. Sounds above 130dB causes pain.

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The top floor of the Ostankino TV Tower in Moscow is located at a height of 360.4 m. Assume a stone is dropped from this top flo

Ulleksa [173]

Answer:

$x=360.4-4.905t^2$

8.57181 s

84.0894561 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

Let distance from ground be x

From equation of motion we have

$s=ut+\frac{1}{2}at^2$

Here, distance covered while the stone is falling will be $360.4-x$

$360.4-x=ut+\frac{1}{2}at^2\\\Rightarrow 360.4-x=\frac{1}{2}9.81t^2\\\Rightarrow 360.4-x=4.905t^2\\\Rightarrow x=360.4-4.905t^2$

The equation is $x=360.4-4.905t^2$

At the ground x = 0

$0=360.4-4.905t^2\\\Rightarrow t=\sqrt{\dfrac{-360.4}{-4.905}}\\\Rightarrow t=8.57181\ s$

The time taken by the stone to fall to the ground is 8.57181 s

$v=u+at\\\Rightarrow v=0+9.81\times 8.57181\\\Rightarrow v=84.0894561\ m/s$

The velocity of the stone when it reaches the ground is 84.0894561 m/s

8 0

2 years ago

Using Newton’s second law, why do you think a cotton ball may not be used as a baseball in a baseball game.

stich3 [128]

Answer:

as its mass and velocity will less so its momentum will be less than that of baseball

3 0

2 years ago

An amusement park ride spins you around in a circle of radius 2.5 m with a speed of 8.5 m/s. If your mass is 75 kg, what is the

zhannawk [14.2K]

B is the answer to this truly did the math

3 0

2 years ago

Read 2 more answers

Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end

iragen [17]

Answer:

The workdone is $W_d =-4400J$

Explanation:

The free body diagram is shown on the first uploaded image

From the question we are given that

The force is on the force gauge $F = 2750 N$

The distance that Magnus pulled the bus $d = 1.60m$

Generally the workdone by the tension force on Magnus is

$Workdone = Force * displacement \ in \ the \ direction \ of \ force$

$W_d = F * (-d)$

This negative sign show that is tension force is in the opposite direction to Magnus movement (i.e the movement of the bus )

Substituting value we have

$Workdone = - 2750 * 1.60$

$=-4400 J$

7 0

2 years ago

If the gas in a container absorbs 275 Joules of heat, has 125 Joules of work done on it, then does 50 Joules of work, what is th

cluponka [151]

Answer:

The increase in the internal energy = 350 J

Explanation:

Given that

Q= 275 J

W= - 125 J

W' = 50 J

W(net)= -125 + 50 = -75 J

Sign -

1.Heat rejected by system - negative

2.Heat gain by system - Positive

3.Work done by system = Positive

4.Work done on the system-Negative

Lets take change in the internal energy =ΔU

We know that

Q= ΔU + W(net)

275 = ΔU -75

ΔU= 275 + 75 J

ΔU=350 J

The increase in the internal energy = 350 J

7 0

2 years ago