Answer: Change in ball's momentum is 1.5 kg-m/s.
Explanation: It is given that,
Mass of the ball, m = 0.15 kg
Speed before the impact, u = 6.5 m/s
Speed after the impact, v = -3.5 m/s (as it will rebound)
We need to find the change in the magnitude of the ball's momentum. It is given by :
So, the change in the ball's momentum is 1.5 kg-m/s. Hence, this is the required solution.
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-3 m/s
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per min
oh I think 8m/s to 3m/s to 0m/s
idk probably -0.08
Answer:
(a) 0.05 Am^2
(b) 1.85 x 10^-3 Nm
Explanation:
width, w = 10 cm = 0.1 m
length, l = 20 cm = 0.2 m
Current, i = 2.5 A
Magnetic field, B = 0.037 T
(A) Magnetic moment, M = i x A
Where, A be the area of loop
M = 2.5 x 0.1 x 0.2 = 0.05 Am^2
(B) Torque, τ = M x B x Sin 90
τ = 0.05 x 0.037 x 1
τ = 1.85 x 10^-3 Nm
Answer:
<em>The number of moles of palladium and tantalum are 0.00037 mole and 0.0000404 mole respectively</em>
Explanation:
Number of mole = reacting mass/molar mass
n = R.m/m.m......................... Equation 1
Where n = number of moles, R.m = reacting mass, m.m = molar mass.
For palladium,
R.m = 0.039 g and m.m = 106.42 g/mol
Substituting theses values into equation 1
n = 0.039/106.42
n = 0.00037 mole
For tantalum,
R.m = 0.0073 and m.m = 180.9 g/mol
Substituting these values into equation 1
n = 0.0073/180.9
n = 0.0000404 mole
<em>Therefore the number of moles of palladium and tantalum are 0.00037 mole and 0.0000404 mole respectively</em>
The temperature will remain constant, at around 100 C, and the volume of water in the pot will decrease, as it turns into steam and floats away from the pot.
