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blagie [28]
2 years ago
10

Samantha wants her friend to wear a bicycle helmet when they go cycling. She wants to explain how a bicycle is designed to provi

de effective protection from head injuries. Write a short explanation about the effectiveness of a bicycle helmet that will help Samantha convince her friend.
Physics
2 answers:
givi [52]2 years ago
7 0
If you don't wear a helmet and let's say you fell off your bike, you can severely injure your head! But if you DO wear a helmet and you fell off your bike, there's about I predict a 98% chance that you won't injure but sometimes it's 100%

hope this helps!<span />
vodomira [7]2 years ago
5 0

Answer:

Explanation:

A bicycle helmet is a very important gear to wear before riding a bicycle because :

1. It protects your head and brain from injury when you fall or crash into a moving car.

2. It reduces the chances of head,face and neck injuries.

It gives you the opportunity to show off your style. Most bicycle helmets have very colourful and great designs that add beauty to your outlook while riding a bicycle.

3. It makes you visible to other motorist using the road especially at night. Bicycle helmets has reflective shiny colours that gets the other road users attention.

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Yupp its c because my dad farted 
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A 2650-lb car is traveling at sea level at a constant speed. its engine is running at 4500 rev/min and is producing 175 ft-lb of
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Check the attached file for the answer.

6 0
2 years ago
Read 2 more answers
A ball weighing 1 lb is attached to a string 2 feet long and is whirled in a vertical circle at a constant speed of 10 ft/sec.
fredd [130]

Explanation:

It is given that,

Mass of the ball, m = 1 lb

Length of the string, l = r = 2 ft

Speed of motion, v = 10 ft/s

(a) The net tension in the string when the ball is at the top of the circle is given by :

F=\dfrac{mv^2}{r}-mg

F=m(\dfrac{v^2}{r}-g)

F=1\ lb\times (\dfrac{(10\ ft/s)^2}{2}-1\ lb\times 32\ ft/s^2)

F = 18 N

(b) The net tension in the string when the ball is at the bottom of the circle is given by :

F=\dfrac{mv^2}{r}+mg

F=m(\dfrac{v^2}{r}+g)

F=1\ lb\times (\dfrac{(10\ ft/s)^2}{2}+1\ lb\times 32\ ft/s^2)

F = 82 N

(c) Let h is the height where the ball at certain time from the top. So,

T=mg(\dfrac{r-h}{r})+\dfrac{mv^2}{r}

T=\dfrac{m}{r}(g(r-h)+v^2)

Since, v^2=u^2-2gh

T=\dfrac{m}{r}(u^2-3gh+gr)

Hence, this is the required solution.

6 0
2 years ago
A charge Q is placed on the x axis at x = +4.0 m. A second charge q is located at the origin. If Q = +75 nC and q = −8.0 nC, wha
Stells [14]

Answer:

23.1 N/C

Explanation:

OP = 3 m , OQ = 4 m

PQ = \sqrt{4^{2}+3^{2}}=5 m

q = - 8 nC, Q = 75 nC

Electric field at P due to the charge Q is

E_{1}=\frac{KQ}{PQ^{2}}=\frac{9\times 10^{9}\times 75\times 10^{-9}}{25}=27 N/C

Electric field at P due to the charge q is

E_{2}=\frac{Kq}{PO^{2}}=\frac{9\times 10^{9}\times 8\times 10^{-9}}{9}=8 N/C

According to the diagram, tanθ = 3/4

Resolve the components of E1 along x axis and along y axis.

So, Electric field along X axis, Ex = - E1 Cos θ

Ex = - 27 x 4 / 5 = - 21.6 N/C

Electric field along y axis, Ey = E1 Sinθ - E2

Ey = 27 x 3 /5 - 8 = 8.2 N/C

The resultant electric field at P is given by

E=\sqrt{E_{x}^{2}+E_{y}^{2}}=\sqrt{(-21.6)^{2}+(8.2)^{2}}=23.1 N/C

3 0
2 years ago
A motor does a total of 480 joules of work in 5.0 seconds to lift a 12-kilogram block to the top of a ramp. The average power de
stepan [7]
Power may be defined as the rate of doing work or the rate of using energy. <span> It is the amount of energy consumed per unit time. It is calculated as follows:

P = E / t
P = 480 / 5
P = 96 W <-----OPTION 3

Hope this answers the question. Have a nice day.</span>
7 0
2 years ago
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