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kramer
2 years ago
6

Water is projected from two rubber pipes at the same speed from one at an angle of 30°and from the other at 60°.why are the rang

es equal?
Physics
1 answer:
cupoosta [38]2 years ago
4 0
Thats hard...im not sure
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Where is the steering nozzle located on a pwc?
Dvinal [7]
At the rear.

PWC stands for personal watercraft, and it is a small powerboat. The main components of a PWC are the hull (body of the boat), deck (surface where people walk/stand), throttle (controls speed), steering nozzle and water intake.
3 0
2 years ago
Read 2 more answers
A block of mass m1 = 3.5 kg moves with velocity v1 = 6.3 m/s on a frictionless surface. it collides with block of mass m2 = 1.7
maxonik [38]
First, let's find the speed v_i of the two blocks m1 and m2 sticked together after the collision.
We can use the conservation of momentum to solve this part. Initially, block 2 is stationary, so only block 1 has momentum different from zero, and it is:
p_i = m_1 v_1
After the collision, the two blocks stick together and so now they have mass m_1 +m_2 and they are moving with speed v_i:
p_f = (m_1 + m_2)v_i
For conservation of momentum
p_i=p_f
So we can write
m_1 v_1 = (m_1 +m_2)v_i
From which we find
v_i =  \frac{m_1 v_1}{m_1+m_2}= \frac{(3.5 kg)(6.3 m/s)}{3.5 kg+1.7 kg}=4.2 m/s

The two blocks enter the rough path with this velocity, then they are decelerated because of the frictional force \mu (m_1+m_2)g. The work done by the frictional force to stop the two blocks is
\mu (m_1+m_2)g  d
where d is the distance covered by the two blocks before stopping.
The initial kinetic energy of the two blocks together, just before entering the rough path, is
\frac{1}{2} (m_1+m_2)v_i^2
When the two blocks stop, all this kinetic energy is lost, because their velocity becomes zero; for the work-energy theorem, the loss in kinetic energy must be equal to the work done by the frictional force:
\frac{1}{2} (m_1+m_2)v_i^2 =\mu (m_1+m_2)g  d
From which we can find the value of the coefficient of kinetic friction:
\mu =  \frac{v_i^2}{2gd}= \frac{(4.2 m/s)^2}{2(9.81 m/s^2)(1.85 m)}=0.49
3 0
2 years ago
Given the indices of refraction n1 and n2 of material 1 and material 2, respectively, rank these scenarios on the basis of the p
lisov135 [29]

Answer:

c>d>f=a>b>e

Explanation:

When a pair of medial has greater difference between the their individual refractive indices with respect to vacuum then it has a greater deviation between the refracted ray and the incident ray.

According to the Snell's law:

\rm refractive\ index\ (n)=\frac{speed\ of\ light\ in\ the\ incident\ medium}{speed\ of\ light\ in\ the\ refracted\ medium}

a)

n_1-n_2=1.33-1.00\\=0.33

b)

n_2-n_1=1.46-1.33

=0.23

c)

n_2-n_1=2.42-1.33\\=1.09

d)

n_2-n_1=1.46-1.00\\=0.46

e)

n_1-n_2=1.50-1.33\\=0.17

f)

n_2-n_1=1.33-1.00\\=0.33

c>d>f=a>b>e

5 0
2 years ago
The k of a material is defined as the resistance of the wire made from that material which is ? long, and in diameter.
Elodia [21]
90 meaters longer than you
8 0
2 years ago
If the wire is replaced by an infinite current sheet with density Js = 0.40 A/m, what would be the magnetic flux (in T · m2) thr
oksian1 [2.3K]

Answer:

\phi _{B} =0.855 T-m^{-2}

Explanation:

given data

density of current sheet = 0.40 A/m

length a = 0.27 m

width b = 0.63 m

For infinite sheet, magnetic field is given as

B = \mu _{O}J

magnetic flux is given as

\phi _{B} = BA

                   = \mu _{O}Jab

                   = 4\pi *0.40*0.27*0.63

\phi _{B} =0.855 T-m^{-2}

6 0
2 years ago
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