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Helen [10]
2 years ago
15

In a particular application involving airflow over a surface, the boundary layer temperature distribution may be approximated as

T−Ts/T[infinity]−Ts=1−exp⁡(−Pr(u[infinity]y)/????) Where y is the distance normal to the surface and the Prandtl number, Pr=cpμ/k=0.7, is a dimensionless fluid property. If T[infinity]=400K, Ts=300K, and u[infinity]/υ=5000 m-1, what is the surface heat flux? 6.11

Physics
1 answer:
Anni [7]2 years ago
8 0

Answer:

The Surface heat flux is -9205 W/m^2

Explanation:

 Explanation is in the following attachment    

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A 4.0 kg block is resting on a rough horizontal table. The coefficient of static friction us is 0.60. The static friction betwee
professor190 [17]

Answer: 24 N

Explanation:

Given that the

Mass m = 4 kg

Coefficient of friction (μ) = 0.60

To calculate the static friction between the block and the table before any attempted motion, you will use the formula; F = (μ)N

Where

F = static friction

N = normal reaction = mg

g = acceleration due to gravity = 9.8 m/^2

Substitutes m, g and (μ) into the formula

F = 0.6 × 4 × 9.8

F = 23.52 N

Therefore, the static friction between the block and the table before any attempted motion is 24 N approximately.

6 0
2 years ago
Technician A says test lights are great for quick tests on non-computerized circuits. Technician B says you can use a test light
Tpy6a [65]

Answer:

that technician A is right

Explanation:

The test lights are generally small bulbs that are turned on by the voltage and current flowing through the circuit in analog circuits, these two values ​​are high and can light the bulb. In digital circuits the current is very small in the order of milliamps, so there is not enough power to turn on these lights.

From the above it is seen that technician A is right

4 0
2 years ago
What type of equilibrium is guaranteed by each condition of equilibrium
Ostrovityanka [42]

Answer: Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium

Explanation: Hope this helped

5 0
2 years ago
A 6.0-cm-diameter, 11-cm-long cylinder contains 100 mg of oxygen (O2) at a pressure less than 1 atm. The cap on one end of the c
butalik [34]

Answer:

The temperature of the gas is 1197.02 K

Explanation:

From ideal gas law;

PV = nRT

Where;

P is the pressure of the gas

V is the volume of the gas

R is ideal gas constant = 8.314 L.kPa/mol.K

T is the temperature of the gas

n is the number of moles of gas

Volume of the gas in the cylindrical container = πr²h

Given;

r = 6/2 = 3 cm = 0.03 m

h = 11 cm = 0.11 m

V = π × (0.03)² × 0.11 = 3.11 × 10⁻⁴ m³ = 0.311 L

number of moles of oxygen gas = Reacting mass / molar mass

=\frac{0.1}{32} = 0.003125, moles

T = \frac{PV}{nR} = \frac{100X0.311}{0.003125X8.314} =1197.02K

Therefore, the temperature of the gas is 1197.02 K

6 0
2 years ago
Julius competes in the hammer throw event. The hammer has a mass of 7.26 kg and is 1.215 m long. What is the centripetal force o
nevsk [136]
In the circular motion of the hammer, the centripetal force is given by
F=m \frac{v^2}{r}
where m is the mass of the hammer, v its tangential speed and r is the distance from the center of the motion, i.e. the length of the hammer.
Using the data of the problem, we find:
F=m \frac{v^2}{r}=(7.26 kg) \frac{(31.95 m/s)^2}{1.215 m}=6100 N
4 0
2 years ago
Read 2 more answers
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