In a particular application involving airflow over a surface, the boundary layer temperature distribution may be approximated as
T−Ts/T[infinity]−Ts=1−exp(−Pr(u[infinity]y)/????) Where y is the distance normal to the surface and the Prandtl number, Pr=cpμ/k=0.7, is a dimensionless fluid property. If T[infinity]=400K, Ts=300K, and u[infinity]/υ=5000 m-1, what is the surface heat flux? 6.11
1 answer:
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Answer:
Snail's speed = = 0.0125m/s
Turtle's speed = = 0.1375m/s
Explanation:
Let the snail's speed be x m/s
The turtle's speed then is 11x m/s
Speed = Distance ÷ Time
Since speed and distance are directly proportional;
The ratio of the distances snail and turtle cover before they meet is x:11x respectively.
Simplified, the ratio of snail distance : turtle distance = 1:11
So snail covers a distance of × 360 = 30m
And turtle covers a distance of × 360 = 330m
The time each took before they met is 40 × 60 = 2400 seconds
Snail's speed = = 0.0125m/s
Turtle's speed = = 0.1375m/s
Answer:
The value of tension on the cable T = 1065.6 N
Explanation:
Mass = 888 kg
Initial velocity ( u )= 0.8
Final velocity ( V ) = 0
Distance traveled before come to rest = 0.2667 m
Now use third law of motion =
- 2 a s
Put all the values in above formula we get,
⇒ 0 = - 2 × a ×0.2667
⇒ a = 1.2
This is the deceleration of the box.
Tension in the cable is given by T = F = m × a
Put all the values in above formula we get,
T = 888 × 1.2
T = 1065.6 N
This is the value of tension on the cable.