Answer: 24 N
Explanation:
Given that the
Mass m = 4 kg
Coefficient of friction (μ) = 0.60
To calculate the static friction between the block and the table before any attempted motion, you will use the formula; F = (μ)N
Where
F = static friction
N = normal reaction = mg
g = acceleration due to gravity = 9.8 m/^2
Substitutes m, g and (μ) into the formula
F = 0.6 × 4 × 9.8
F = 23.52 N
Therefore, the static friction between the block and the table before any attempted motion is 24 N approximately.
Answer:
that technician A is right
Explanation:
The test lights are generally small bulbs that are turned on by the voltage and current flowing through the circuit in analog circuits, these two values are high and can light the bulb. In digital circuits the current is very small in the order of milliamps, so there is not enough power to turn on these lights.
From the above it is seen that technician A is right
Answer: Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium
Explanation: Hope this helped
Answer:
The temperature of the gas is 1197.02 K
Explanation:
From ideal gas law;
PV = nRT
Where;
P is the pressure of the gas
V is the volume of the gas
R is ideal gas constant = 8.314 L.kPa/mol.K
T is the temperature of the gas
n is the number of moles of gas
Volume of the gas in the cylindrical container = πr²h
Given;
r = 6/2 = 3 cm = 0.03 m
h = 11 cm = 0.11 m
V = π × (0.03)² × 0.11 = 3.11 × 10⁻⁴ m³ = 0.311 L
number of moles of oxygen gas = Reacting mass / molar mass


Therefore, the temperature of the gas is 1197.02 K
In the circular motion of the hammer, the centripetal force is given by

where m is the mass of the hammer, v its tangential speed and r is the distance from the center of the motion, i.e. the length of the hammer.
Using the data of the problem, we find: