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Marina86 [1]
2 years ago
6

Two particles collide and stick together. If no external forces act on the two particles, which of the following is correct for

the change in total momentum Δp and the change in total kinetic energy ΔK of the two particles?
a. p<0, K<0.
b. p<0, K=0.
c. p=0, K<0.
d. p=0, K=0.
e. p=0, K>0.
Physics
1 answer:
Semmy [17]2 years ago
4 0

Answer:

c.\Delta p=0 and \Delta k

Explanation:

We are given that two particles collide  and stick together.

If there is no external force act on the two particles then ,it is inelastic collision.

Inelastic collision: There is some loss of kinetic energy but the momentum is conserved.

According to law of conservation of momentum

Initial momentum=Final momentum

Change in momentum=Final momentum-Initial momentum=0

Change in momentum=\Delta p=0

Initial kinetic energy is greater than final kinetic energy.

Change in kinetic energy=Final kinetic energy-kinetic energy=- negative

\Delta k

Hence, option c is true.

c.\Delta p=0 and \Delta k

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2.5

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Hicham El Guerrouj of Morocco holds the world record in the 1500 m running race. He ran the final 400 m in a time of 51.9 s.
konstantin123 [22]

Answer: His average speed in mph over the last 400 m is 7.7 m/s.

Explanation:

Given: Hicham El Guerrouj of Morocco holds the world record in the 1500 m running race. He ran the final 400 m in a time of 51.9 s.

We know that , speed = \dfrac{distance}{time}

Here , distance = 400m and time = 51.9 s

Then, speed =  \dfrac{400}{51.9}\approx7.7\ m/s

Hence, his average speed in mph over the last 400 m is 7.7 m/s.

5 0
2 years ago
A stiff wire 50.0 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the l
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Answer:

Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis

Explanation:

The stiff wire 50.0cm long bent at a right angle in the middle

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\frac{y}{x} = 2

tan θ = 2

Therefore,

slope m = tan θ = y / x

\theta=\tan^-^1(2)=63.4^0

Then length of each section is 25.0cm

so, length vector of the wire is

\hat I= (-25.0)\hat k +(25.0) \cos 63.4^0 \hati +(25.0) \sin63.4^0 \hatJ\\\\\hat I = (11.2) \hat i + (22.4) \hat j - (23.0) \hat k

And magnetic field is B = (0.318T)i

Therefore,

\bar F = \hat I (\bar l \times \bar B)

\bar F = (20.0)[(0.112m)i +(0.224m)j-(0.250m)k \times 90.318T)i]

= (20.0)(i(0)+j(-0.250)(0.318T)+k[0-(0.224m)(0.318T)]\\\\=(20.0)(-0.250)(0.318)j-(20.0)(0.224)(0.318T)\\\\=-(1.59N)j-(1.425N)k

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F = \sqrt{(-1.59N)^2+(-1.425N)^2\\} \\F = 2.135N

Direction is

\alpha = \tan^-^1(\frac{-1.425N}{-1.59N} )\\\\= 41.8^0

Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis

5 0
2 years ago
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Answer:

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2 years ago
Mars has two moons, Phobos and Deimos. Phobos orbits Mars at a distance of 9380 km from Mars's center, while Deimos orbits at 23
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Answer:

The ratio is   \frac{T_1}{T_2}  = 3.965

Explanation:

From the question we are told that

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Generally from Kepler's third law

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=>  [\frac{T_1}{T_2} ]^2 =  [\frac{R_1}{R_2} ]^3

Here T_1 is the period of Deimos

and  T_1 is the period of  Phobos

So

      [\frac{T_1}{T_2} ] =  [\frac{R_1}{R_2} ]^{\frac{3}{2}}

=>    \frac{T_1}{T_2}  =  [\frac{23500 }{9380} ]^{\frac{3}{2}}]

=>    \frac{T_1}{T_2}  = 3.965

   

8 0
2 years ago
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