Answer:
μs = 0.36
Explanation:
Assuming no other forces acting on the cup while the car is decelerating, the friction force is responsible for any horizontal movement of the cup.
If the cup is on the verge of starting to slide, the friction force can be expressed as follows:
Ff = -μs*N = -μs*m*g
This force produces a deceleration from 45 Kmh to rest, in 3.5 s or more.
Converting 45 kmh to m/s, we have:
We can find the acceleration, just applying the definition, with vf =0, as follows:
According to Newton's 2nd law, we can write the following expression:
F = m*a = -μs*m*g
Simplifying common terms, we can solve for μs, as follows:
μs = 
Answer:
114.86%
Explanation:
In both cases, there is a vertical force equal to the sprinter's weight:
Fy = mg
When running in a circle, there is an additional centripetal force:
Fx = mv²/r
The net force is found with Pythagorean theorem:
F² = Fx² + Fy²
F² = (mv²/r)² + (mg)²
F² = m² ((v²/r)² + g²)
F = m √((v²/r)² + g²)
Compared to just the vertical force:
F / Fy
m √((v²/r)² + g²) / mg
√((v²/r)² + g²) / g
Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:
√((12²/26)² + 9.8²) / 9.8
1.1486
The force is about 114.86% greater (round as needed).
Transverse waves travel on a direction that is perpendicular to the motion of the particles (or whatever medium is waving) So the particles must be moving east to west, which is transverse to the north-south motion of the wave
Answer:
It will take 4 sec rock to comes its original point
Explanation:
It is given that the rock comes to its original point
So displacement S = 0 m
Initial velocity u = 19.6 m/sec
Acceleration due to gravity 
According to second equation of motion 
t = 4 sec
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
b
Explanation:
From the question we are told that
The image distance is 
The value of the image is negative because it is on the same side with the corrective glasses
The object distance is 
The reason object distance is because the object father than it being picture by the eye
General focal length is mathematically represented as
substituting values
=>
Generally the power of the corrective lens is mathematically represented as
substituting values
