Using the right-hand rule from your lessons, determine the directions of the electrical current and magnetic field of the electr
omagnet. Create an illustration of these perpendicular forces and include it below. (You can take a picture of your illustration or use an online drawing program to make your illustration.)
1 answer:
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Answer:
T= 354.65 N
Explanation:
Given that
ρ= 7800 kg/m³
L= 58 cm
d=1.34 mm
f= 311 Hz
T= Tension
Speed of wave ,V
V = f λ
V = f L
V= 311 x 0.58 m/s
V=180.38 m/s
Area of cross sectional
A= πr² mm²
A= 3.14 x 0.67² mm²
A=1.41 mm²
Mass = Density x Volume
m=0.0109 kg/m
Tension ,T
T= 0.0109 x 180.38² N
T= 354.65 N
Answer:
Q=1005 J
t= 0.67 sec
Explanation:
Lets take condition of room is 1 atm and 25°C.
Heat capacity ,c = 21 J /K.mol
If we assume that air is ideal gas that
P V = n R T
V= 107250 L
At STP number of moles given as
V=22.4 L at S.T.P.
n=4787.94 moles
n= 4.784 Kmoles
So heat required to raise 10°C temperature
Q = n x c x ΔT
Q = 4.78794 x 21 x 10
Q=1004.64 J
Time t
t= Q/P
P= 1.5 KW
t = 1.004.64 /1.5
t= 0.66 sec