Answer:
The angular magnification is 
Explanation:
From the question we are told
The focal length is 
The near point is 
The angular magnification is mathematically represented as

Substituting values

Answer:
59cm
Explanation:
angular velocity = 0.8 rad/s
linear velocity = angular velocity * radius
=0.8rad/s * 5m
= 4 m/s
wavelength = (V + U)/F
where,
V is the velocity of the wave
U is the velocity of the source
F is the frequency of the source.
wavelength = (350 m/s + 4 m/s ) / 600 Hz
Wavelength = 0.59m or 59 cm
Answer:
Magnification, m = 3
Explanation:
It is given that,
Focal length of the lens, f = 15 cm
Object distance, u = -10 cm
Lens formula :

v is image distance

Magnification,

So, the magnification of the lens is 3.
Answer:
a) Fₓ = 23.5 N
b) Net force = Fₓ
Explanation:
An image of the question as described is attached to this solution.
From the image attached, the forces acting on the box include the weight of the box, the normal reaction of the surface on the box, the applied force on the box and the Frictional force opposing the motion of the box (which is negligible and equal to 0)
a) From the diagram, the horizontal component of the force is
Fₓ = 25 cos 20° = 23.49 N = 25 N
b) Again, from the diagram attached, doing a force balance on the box, in the horizontal direction, we obtain
Net force = Fₓ - Frictional force
But frictional force is 0 N
Net force = Fₓ
Hope this Helps!!!