Answer:
The value is 
Explanation:
From the question we are told that
The radius is 
The distance of point A from the center is 
The distance of point B from the center is 
The slope is 
Generally the difference in potential between A and B is mathematically represented as
![V_{AB} = V_A -V_B = k * q [\frac{1}{a} - \frac{1}{b} ]](https://tex.z-dn.net/?f=V_%7BAB%7D%20%3D%20%20V_A%20%20%20-V_B%20%20%3D%20%20k%20%2A%20q%20%20%5B%5Cfrac%7B1%7D%7Ba%7D%20-%20%5Cfrac%7B1%7D%7Bb%7D%20%20%5D)
Let consider the position where 
So
![V_{AB} = V_A -V_B = k * q [\frac{1}{a} - \frac{1}{ \infty} ]](https://tex.z-dn.net/?f=V_%7BAB%7D%20%3D%20%20V_A%20%20%20-V_B%20%20%3D%20%20k%20%2A%20q%20%20%5B%5Cfrac%7B1%7D%7Ba%7D%20-%20%5Cfrac%7B1%7D%7B%20%5Cinfty%7D%20%20%5D)
Here k is the coulombs constant with value 
=> ![V_{AB} = V_A -V_B = 9*10^{9} * q [\frac{1}{0.08} - 0 ]](https://tex.z-dn.net/?f=V_%7BAB%7D%20%3D%20%20V_A%20%20%20-V_B%20%20%3D%20%209%2A10%5E%7B9%7D%20%2A%20q%20%20%5B%5Cfrac%7B1%7D%7B0.08%7D%20-%200%20%5D)
=>
=> 
Generally the slope is mathematically represented as
At the position of A i.e r = a
=> 
=> 
=>
Answer: a) v = ω /k, b) v = - ωAcos( kx −ωt)
Explanation:
y(x,t)=Asin(kx−ωt) defines the wave equation.
a)
We are asked to find wave speed (v)
Recall that v = fλ
From the wave equation above,
k = 2π/ λ where k is the wave number and λ is the wavelength, λ = 2π /k
ω = 2πf where f is the frequency and ω is the angular frequency.
f = ω/ 2π.
By substituting for λ and ω into the wave speed formulae, we have that
v =( ω/ 2π) × (2π /k)
v = ω/k
b)
y(x,t)=Asin(kx−ωt)
The first derivative of y with respect to x give the velocity (vy)
By using chain rule, we have that
v = dy/dt = A cos( kx −ωt) × (−ω)
v = - ωAcos( kx −ωt)
Answer:
Pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²
Explanation:
Force applied on baseball = 30 times weight of the ball.
Weight of ball = mg, where m is the mass of ball and g is acceleration due to gravity value.
We have force applied is also equal to product of mass and acceleration.
F = ma = 30 x mg
a = 30g
So, pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²
Answer:
option b
Explanation:
There is an object pulled inward in an electric field.
We have to find out of the four options given which is true.
a) The object has a neutral charge is false since when electric field pulls the object inward, there is a charge inside.
b) The object has a charge opposite that of the field, this option is correct since there will be an equal and opposite charge created by the object
c) The object has a negative charge will be correct only if the original charge was positive hence wrong
d) The object has a charge the same as that of the field is incorrect since this would be opposite the charge
So only option b is right
Answer:
Explanation:
The energy stored in the spring is used to throw the ball upwards . Let the height reached be h
stored energy of spring = 1/2 k y² , k is spring constant and y is compression created in the spring
stored energy of spring = potential energy of the ball
1/2 k y² = mgh , m is mass of the ball , h is height attained by ball
.5 k x .055² = .025 x 2.84
.0015125 k = .071
k = .071 / .0015125
= 46.9 N / m .
