<h3><u>Answer;</u></h3>
<em>Work = 125 joules </em>
<h3><u>Explanation and solution</u>;</h3>
- Work is the product of force and the distance covered. Therefore, Work = force × distance.
- Work is measured in joules.
- Work is also a change in energy, such that work is done when energy changes, so when kinetic energy, or potential energy changes the there is work being done.
Thus; kinetic energy = work done
Kinetic energy = 1/2mv²
= 1/2 × 10× 5²
= 5 × 25
= 125 joules
Hence, work done is 125 joules.
Answer:
To obtain the power, we first need to find the work made by the force.
1) To calculate the work, we need the next equation:
So the force is given by the problem so our mission is to find 'dx' in terms of 't'
2) we know that:
So we have:
Then:
3) Finally, we replace everything:
After some calculation, we have as a result that the work is:
161.9638 J.
4) To calculate the power we need the next equation:
So
P = 161.9638/4.7 = 34.46 W
The answer for this change in the magnitude of momentum is the same for both because momentum is always conserved so both vehicles have the identical change.
So for determining who has the greater change in kinetic energy, momentum (P) = mv so P^2 = m^2 v^2 P^2 / 2m = 1/2 m v^2 = energy So the weightier the mass the smaller the energy change for the same momentum change so in here, the car has a greater change in kinetic energy.
Answer:
Wet surfaces areaA=+25.3ft^2
Explanation:
Using F= K×A× S^2
Where F= drag force
A= surface area
S= speed
Given : F=996N S=20mph A= 83ft^2
K = F/AS^2=996/(83×20^2)
K= 996/33200 = 0.03
1215= (0.03)× A × 18^2
1215=9.7A
A=1215/9.7=125.3ft^2
