A sled of mass m is being pulled horizontally by a constant horizontal force of magnitude F. The coefficient of kinetic friction
1 answer:
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Answer:
I = 215.76 A
Explanation:
The direction of magnetic field produced by conductor 1 on the location of conductor 2 is towards left. Based on Right Hand Rule -1 and taking figure 21.3 as reference, the direction of force Fm due to magnetic field produced at C_2 is shown above. The force Fm balances the weight of conductor 2.
Fm = u_o*I^2*L/2*π*d
where I is the current in each rod, d = 0.0082 m is the distance 27rId
between each, L = 0.85 m is the length of each rod.
Fm = 4π*10^-7*I^2*1.1/2*π*0.0083
The mass of each rod is m = 0.0276 kg
F_m = mg
4π*10^-7*I^2*1.1/2*π*0.0083=0.0276*9.8
I = 215.76 A
note:
mathematical calculation maybe wrong or having little bit error but the method is perfectly fine
Initially, the energies are:
At final point, the energies are:
Using conservation law of energy,
The equation is further simplified as:
Answer:
2.45 m
Explanation:
First of all, we have to calculate the time of flight of the book, by using the equation for the vertical motion:
where
h = 1.19 m is the vertical distance covered by the book
g = 9.8 m/s^2 is the acceleration of gravity
t is the time of flight
Solving for t,
Now we can find the horizontal distance covered by the book, which is given by
where
is the horizontal velocity
t = 0.49 s is the time of flight
Substituting,
So the book lands 2.45 m away.