A sled of mass m is being pulled horizontally by a constant horizontal force of magnitude F. The coefficient of kinetic friction
1 answer:
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Answer:
0.018 J
Explanation:
The work done to bring the charge from infinity to point P is equal to the change in electric potential energy of the charge - so it is given by
where
is the magnitude of the charge
is the potential difference between point P and infinity
Substituting into the equation, we find
Answer:
(2) −1 e
Explanation:
A quark is the lightest elementary particles which form hadron such as proton and neutron. A quark has fractional charge.
Up, charm and top quarks have charge where as down, strange and bottom quarks have
charge.
The antiparticle of up quark is antiup quark and has charge charge.
The antiparticle of down quark is antidown quark and has charge charge.
An antibaryon is composed of two anti-up quark and one anti-down quark.
Net charge of the anti-baryon is:
Thus, antibaryon has -1e charge.
I attached the missing picture.
We can figure this one out using the law of conservation of energy.
At point A the car would have potential energy and kinetic energy.
Then, while the car is traveling down the track it loses some of its initial energy due to friction:
So, we know that the car is approaching the point B with the following amount of energy:
The law of conservation of energy tells us that this energy must the same as the energy at point B.
The energy at point B is the sum of car's kinetic and potential energy:
As said before this energy must be the same as the energy of a car approaching the loop:
Now we solve the equation for
:
We can figure this one out using the law of conservation of energy.
At point A the car would have potential energy and kinetic energy.
Then, while the car is traveling down the track it loses some of its initial energy due to friction:
So, we know that the car is approaching the point B with the following amount of energy:
The law of conservation of energy tells us that this energy must the same as the energy at point B.
The energy at point B is the sum of car's kinetic and potential energy:
As said before this energy must be the same as the energy of a car approaching the loop:
Now we solve the equation for