Answer:
230 m/s northeast, 1.8 m/s up
Explanation:
204 kilometres = 204000 metres
15.0 minutes = 900 seconds
Velocity = Distance / Time
= 204000 / 900
= 230 m/s northeast (to 2 sf.)
1.6km = 1600 metres
Velocity = 1600 / 900
= 1.8 m/s up (to 2 sf.)
Answer:
longer than
Explanation:
given,
time of nap = 10 min
speed of orbiting earth = 8000 m/s
c is the speed of light
using the equation of time dilation

now inserting all the values


t' = 10.001 s
on solving the above equation we will get a value greater than 10minutes.
hence, On earth time of nap measured will be longer than 10 min
In order for two vectors to add to zero, they must have the same magnitude and point in opposite directions.
Two perpendicular vectors, by definition, make a right angle with each other whereas two vectors pointing in opposite directions form a straight line.
Because of this, two perpendicular vectors with nonzero magnitudes will never add to zero.
Answer:
magnetic flux ΦB = 0.450324 ×
weber
current I = 1.02484
A
Explanation:
Given data
length a = 2.2 cm = 0.022 m
width b = 0.80 cm = 0.008 m
Resistance R = 0.40 ohms
current I = 4.7 A
speed v = 3.2 mm/s = 0.0032 m/s
distance r = 1.5 b = 1.5 (0.008) = 0.012
to find out
magnitude of magnetic flux and the current induced
solution
we will find magnitude of magnetic flux thorough this formula that is
ΦB = ( μ I(a) /2 π ) ln [(r + b/2 ) /( r -b/2)]
here μ is 4π ×
put all value
ΦB = (4π ×
4.7 (0.022) /2 π ) ln [(0.012+ 0.008/2 ) /( 0.012 -0.008/2)]
ΦB = 0.450324 ×
weber
and
current induced is
current = ε / R
current = μ I(a) bv / 2πR [(r² ) - (b/2 )² ]
put all value
current = μ I(a) bv / 2πR [(r² ) - (b/2 )² ]
current = 4π ×
(4.7) (0.022) (0.008) (0.0032) / 2π(0.40) [(0.012² ) - (0.008/2 )² ]
current = 1.02484
A
The climber move 0.19 m/s faster than surfer on the nearby beach.
Since both the person are on the earth, and moves with the constant angular velocity of earth, however there linear velocity is different.
Number of seconds in a day, t=24*60*60=86400 sec
The linear speed on the beach is calculated as
V1=
Here, t is the time
Plugging the values in the above equation
V1=
=465.421 m/s
Velocity on the mountain is calculated as
V2=
Plugging the values in the above equation
V2=
=465.61 m/s
Therefore person on the mountain moves faster than the person on the beach by 465.61-465.421=0.19 m/s