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Elden [556K]
2 years ago
7

A helicopter flies 250 km on a straight path in a direction 60° south of east. The east component of the helicopter’s displaceme

nt is km.

Physics
2 answers:
GaryK [48]2 years ago
8 0

Given that,

Distance in south-west direction = 250 km

Projected angle to east = 60°

East component = ?

since,

cos ∅ = base/hypotenuse

base= hyp * cos ∅

East component = 250 * cos 60°

East component = 125 km

Lorico [155]2 years ago
8 0

Answer:

125km

Explanation:

the east component is given by the cosine function of the given angle.

because of the triangle that is formed between the east component end the south-east component

cos\theta=\frac{adjacent Leg}{hypotenuse}

in this case the angle is: \theta =60

the adyacent Leg is the east component Ec

and the hypotenuse: d=250km

so:

cos60=\frac{Ec}{250km}

we clear for the east component:

Ec=(250km)(cos60)\\Ec=(250km)(0.5)\\Ec=125km

you can see the the triangle in the attached image, where the blue line is the east component

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