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Alexandra [31]
1 year ago
13

Driving your Ferrari through the Italian countryside at a speedy 88 m/s, you approach an opera diva singing a high C (1,046 Hz).

What note will you actually hear as you approach? (Assume a speed of sound of 340 m/s.)
Physics
1 answer:
MrRissso [65]1 year ago
7 0

Answer:

You will hear the note E₆

Explanation:

We know that:

Your speed = 88m/s

Original frequency = 1,046 Hz

Sound speed = 340 m/s

The Doppler effect says that:

f' = \frac{v \pm v0 }{v \mp vs}*f

Where:

f = original frequency

f' = new frequency

v = velocity of the sound wave

v0 = your velocity

vs = velocity of the source, in this case, the source is the diva, we assume that she does not move, so vs = 0.

Replacing the values that we know in the equation we have:

f' = \frac{340 m/s + 88m/s}{340 m/s} *1,046 Hz = 1,316.73 Hz

This frequency is close to the note E₆ (1,318.5 Hz)

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Two children, Ahmed and Jacques, ride on a merry-go-round. Ahmed is at a greater distance from the axis of rotation than Jacques
Alex

Answer:

A. Ahmed has a greater tangential speed than Jacques.

D. Jacques and Ahmed have the same angular speed.

Explanation:

Kinematics of the merry-go-round

The tangential speed of the merry-go-round is calculated using the following formula:

v = ω*R

Where:

v is the tangential speed in meters/second (m/s)

ω is the angular speed in radians/second (rad/s)

R is the angular speed in meters (m)

Data

dA = RA  : Ahmed distance to the axis of rotation

dJ = RJ   : Jacques distance to the axis of rotation

Problem development

We apply the formula (1)

v = ω*R

vA= ω*RA : Ahmed  tangential speed

vJ= ω*RJ  :  Jacques  tangential speed

Ahmed is at a greater distance from the axis of rotation than Jacques, then,

RA ˃ RJ and Ahmed and Jacques have the same  speed ω, then:

vA ˃ vJ

6 0
2 years ago
A wire loop is suspended from a string that is attached to point P in the drawing. When released, the loop swings downward, from
Naddik [55]

Complete Question

The complete question iws shown on the first uploaded image  

Answer:

a

    y \to z \to x

b

  x \to z \to y

Explanation:

Now looking at the diagram let take that the magnetic field is moving in the x-axis

 Now the magnetic force is mathematically represented as

             F =  I L x B

Note (The x is showing cross product )

Note the force(y-axis) is perpendicular to the field direction (x-axis)

Now when the loop is swinging forward

 The motion of the loop is  from   y to z to to x to y

Now since the force is perpendicular to the motion(velocity) of the loop

Hence the force would be from z to y and back to z  

and from lenze law the induce current opposes the force so the direction will be from y to z to x

Now when the loop is swinging backward

   The motion of the induced current will now be   x to z to y

 

5 0
2 years ago
A carnot engine operates between two heat reservoirs at temperatures th and tc. an inventor proposes to increase the efficiency
Sonja [21]
The efficiency of the first Carnot engine is 
n1 = 1 - Th/T
The efficiency of the second Carnot engine is
n2 = 1 - T/Tc
The total efficiency of the engines put in series is
n = 1 - Th/Tc
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5 0
2 years ago
If a 1.50 kg mass revolves at the end of a string 0.50 m long, and its tangential speed is 6.0 m/s, calculate the centripetal fo
rosijanka [135]
You should get about 110 for an answer
5 0
2 years ago
Read 2 more answers
For sprinters running at 12 m/s around a curved track of radius 26 m, how much greater (as a percentage) is the average total fo
Snezhnost [94]

Answer:

114.86%

Explanation:

In both cases, there is a vertical force equal to the sprinter's weight:

Fy = mg

When running in a circle, there is an additional centripetal force:

Fx = mv²/r

The net force is found with Pythagorean theorem:

F² = Fx² + Fy²

F² = (mv²/r)² + (mg)²

F² = m² ((v²/r)² + g²)

F = m √((v²/r)² + g²)

Compared to just the vertical force:

F / Fy

m √((v²/r)² + g²) / mg

√((v²/r)² + g²) / g

Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:

√((12²/26)² + 9.8²) / 9.8

1.1486

The force is about 114.86% greater (round as needed).

5 0
1 year ago
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