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denis-greek [22]
2 years ago
5

What is the speed of light (in m/s) in air? (Enter your answer to at least four significant figures. Assume the speed of light i

n a vacuum is 2.997 ✕ 108 m/s.) m/s What is the speed of light (in m/s) in polystyrene? m/s
Physics
1 answer:
jenyasd209 [6]2 years ago
8 0

Answer:

The speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

Explanation:

To find the speed of light in air and in polystyrene we need to use the following equation:

c_{m} = \frac{c}{n}

Where:

c_{m}: is the speed of light in the medium

n: is the refractive index of the medium

In air:

c_{a} = \frac{c}{n_{a}} = \frac{2.997 \cdot 10^{8} m/s}{1.0003} = 2.996 \cdot 10^{8} m/s

In polystyrene:

c_{p} = \frac{c}{n_{p}} = \frac{2.997 \cdot 10^{8} m/s}{1.6} = 1.873 \cdot 10^{8} m/s  

Therefore, the speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

I hope it helps you!

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A person wants to lose weight by "pumping iron". The person lifts an 80 kg weight 1 meter. How many times must this weight be li
statuscvo [17]

Answer:

37357 sec  

or 622 min

or 10.4 hrs

Explanation:

GIVEN DATA:

Lifting weight 80 kg

1 cal = 4184 J

from information given in question we have

one lb fat consist of 3500 calories = 3500 x 4184 J

= 14.644 x 10^6 J  

Energy burns in 1 lift = m g h

                                  = 80 x 9.8 x 1 = 784 J

lifts required = \frac{(14.644 x 10^6)}{784}

                      = 18679

from the question,

1 lift in 2 sec.

so, total time = 18679 x 2 = 37357 sec  

or 622 min

or 10.4 hrs

3 0
2 years ago
You and your dog are walking along a pond. Your dog looks into the still water and is startled to see its reflection. Which phen
attashe74 [19]

You just identified the image as a "reflection", so it's a pretty good bet that
the phenomenon involves reflection somehow.

Your dog can see his reflection in a mirror inside the house just as easily
as in the surface of the pond.  My dogs do it all the time.  The phenomenon
doesn't require water.

It's reflection of light waves.

3 0
2 years ago
Read 2 more answers
Greg walks on a straight road from his home to a convenience store 3.0 km away with a speed of 6.0 km/h. On reaching the store h
VladimirAG [237]

This question was apprently selected from the "Sneaky Questions" category.

The store is 3 km from his home, and he walks there with a speed of 6 km/hr.  So it takes him (3 km) / (6 km/hr)  =  1/2 hour to get to the store.

That's 30 minutes.  So the whole part-(a.) of the question refers to only that part of the trip, and we don't care what happens once he reaches the store.  

a). Over the first 30 minutes of his travel, Greg walks 3.0 km on a straight road, and he ends up 3.0 km away from where he started.

Average speed = (distance/time) = (3.0 km) / (1/2 hour) = <em>6.0 km/hr</em>

Average velocity = (displacement/time) = (3.0 km) / (1/2 hour) = <em>6.0 km/hr</em>

There's probably some more questions in part-(b.) where you'd need to use Greg's return trip to find the answers, but johnaddy210 is only asking us for part-(a.).

8 0
2 years ago
Read 2 more answers
A bullet blasts from the barrel of a gun upward in the vertical direction with an initial speed of 700 m/s . Find the maximum al
ryzh [129]

The maximum altitude that the bullet will reach is the point at which its velocity is zero. The equation that may be used in order to determine the altitude is,

<span>                                   D = ((Vi)2 – (Vf)2)/2g</span>

Where Vi and Vf are the initial and final velocities, respectively. g is the deceleration due to gravity.

Substituting the known values,

<span>                                    D = ((700 m/s)2 – (0 m/s)2) / (2(-9.8 m/s2))</span>

<span>                                    D = 25000 m</span>

 

Thus, the maximum height is 25000 m.

 

For the time needed to reach it, we use the equation,

<span>                                    Vf = Vi – (g)(t)</span>

Substituting,

<span>                                    0 = 700 m/s – (-9.8 m/s2)(t)</span>

The value of t is equal to 71.43 s.

<span> </span>

6 0
2 years ago
In a certain clock, a pendulum of length L1 has a period T1 = 0.95s. The length of the pendulum
gulaghasi [49]

Answer:

Ratio of length will be \frac{L_2}{L_1}=1.108

Explanation:

We have given time period of the pendulum when length is L_1 is T_1=0.95sec

And when length is L_2 time period T_2=1sec

We know that time period is given by

T=2\pi \sqrt{\frac{L}{g}}

So 0.95=2\pi \sqrt{\frac{L_1}{g}}----eqn 1

And 1=2\pi \sqrt{\frac{L_2}{g}}-------eqn 2

Dividing eqn 2 by eqn 1

\frac{1}{0.95}=\sqrt{\frac{L_2}{L_1}}

Squaring both side

\frac{L_2}{L_1}=1.108

8 0
2 years ago
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