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Answer:
The magnitude of the torque on the loop due to the magnetic field is
.
Explanation:
Given that,
Diameter = 10 cm
Current = 0.20 A
Magnetic field = 0.30 T
Unit vector
We need to calculate the torque on the loop
Using formula of torque

Where, N = number of turns
A = area
I = current
B = magnetic field
Put the value into the formula


Hence, The magnitude of the torque on the loop due to the magnetic field is
.
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T=m1a+m2a
a=v^2/r v=r*w w=2πF--->a=r(2f)^2 <r1 for m1 and r2 for m2>
T=(m1r1+m2r2)(2πf)^2 <i factored out (2πf)^2
To solve this problem we will apply the first law of thermodynamics which details the relationship of energy conservation and the states that the system's energy has. Energy can be transformed but cannot be created or destroyed.
Accordingly, the rate of work done in one cycle and the heat transferred can be expressed under the function,

Substitute 1W for
and 1.5 W for 


Now calculcate the rate of specific internal energy increase,



The rate of specific internal energy increase is 1.6667W/kg