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horsena [70]
2 years ago
11

The peregrine falcon is the world's fastest known bird and has been clocked diving downward toward its prey at constant vertical

velocity of 97.2 m/s. If the falcon dives straight down from a height of 100. m, how much time does this give a rabbit below to consider his next move as the falcon begins his descent?
Physics
2 answers:
Sergio [31]2 years ago
7 0
100m / 97.2m/s = 1.0288 seconds
attashe74 [19]2 years ago
5 0

Answer:

Time, t = 1.02 seconds

Explanation:

It is given that,

Velocity of bird, v = 97.2 m/s

If the falcon dives straight down from a height of 100 m, d = 100 m

We need to find the time this give a rabbit below to consider his next move as the falcon begins his descent. Time can be calculated as :

t=\dfrac{d}{v}

t=\dfrac{100\ m}{97.2\ m/s}

t = 1.02 seconds

Hence, this is the required solution.

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Technician A says that the use of some RTV sealants to seal components on an engine can damage the oxygen sensor. Technician B s
netineya [11]

Answer: The correct option is C(both A and B)

Explanation:

In engine chambers, internal combustion of fuel is used to produce mechanical energy.

RTV ( Room Temperature Vulcanising) sealants are silicon products used for the sealing purpose of the engine component. As the name implies once exposed to air, it solidifies. However, it has a negative effect on the oxygen sensor of the engine components by makes a coating over the sensors with the silicone film and, after a time, will affect the operation performed by them. Therefore Technician A is correct.

Technician B is equally correct in that an engine need to be lubricated with oil to help cool the moving part while on. But in order to ensure that oil reaches all movable parts a common method know as heavy-duty reversible spin drills is applied. This method regulates the flow of oil using the engine.

7 0
2 years ago
To move a suitcase up to the check-in stand at the airport a student pushes with a horizontal force through a distance of 0.95 m
hoa [83]

Answer:

33.68 N

Explanation:

Data

W= 32J

d- 0.95m

F= ?

W=Fd

They are asking for the magnitude which is the force, so you need to solve for force.

F=W/d

= 32J/ 0.95m

= 33.68 N

3 0
2 years ago
Two billiard balls of equal mass move at right angles and meet at the origin of an xy coordinate system. Initially ball A is mov
frez [133]

Answer:

Speed of ball A after collision is 3.7 m/s

Speed of ball B after collision is 2 m/s

Direction of ball A after collision is towards positive x axis

Total momentum after collision is m×4·21 kgm/s

Total kinetic energy after collision is m×8·85 J

Explanation:

<h3>If we consider two balls as a system as there is no external force initial momentum of the system must be equal to the final momentum of the system</h3>

Let the mass of each ball be m kg

v_{1} be the velocity of ball A along positive x axis

v_{2} be the velocity of ball A along positive y axis

u be the velocity of ball B along positive y axis

Conservation of momentum along x axis

m×3·7 = m× v_{1}

∴  v_{1} = 3.7 m/s along positive x axis

Conservation of momentum along y axis

m×2 = m×u + m× v_{2}

2 = u +  v_{2} → equation 1

<h3>Assuming that there is no permanent deformation between the balls we can say that it is an elastic collision</h3><h3>And for an elastic collision, coefficient of restitution = 1</h3>

∴ relative velocity of approach = relative velocity of separation

-2 =  v_{2} - u → equation 2

By adding both equations 1 and 2 we get

v_{2} = 0

∴ u = 2 m/s along positive y axis

Kinetic energy before collision and after collision remains constant because it is an elastic collision

Kinetic energy = (m×2² + m×3·7²)÷2

                         = 8·85×m J

Total momentum = m×√(2² + 3·7²)

                             = m× 4·21 kgm/s

3 0
2 years ago
A cannon Is fired from the edge of a small clip the height of the clear is 80.0 at the cannonball inspired with a perfectly hori
Nutka1998 [239]

Answer:

The cannonball fly horizontally before it strikes the ground, S = 323.25 m

Explanation:

Given data,

The height of the cliff, h = 80 m

The horizontal velocity of the cannonball, Vₓ = 80 m/s

The range of the cannon ball with initial vertical velocity is zero is given by the formula,

                           S=\frac{V_{x}\sqrt{2gh}}{g}

                           S=\frac{80\sqrt{2\times9.8\times80}}{9.8}

                           S = 323.25 m

Hence, the cannonball fly horizontally before it strikes the ground, S = 323.25 m

7 0
2 years ago
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Describe a theme-park ride that has constant speed but changing velocity.<br><br> Thank you!
photoshop1234 [79]
How about a carousel (merry go round).
For any one horse or rider, Speed is constant but direction keeps changing, so velocity does too.
8 0
2 years ago
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