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horsena [70]
2 years ago
11

The peregrine falcon is the world's fastest known bird and has been clocked diving downward toward its prey at constant vertical

velocity of 97.2 m/s. If the falcon dives straight down from a height of 100. m, how much time does this give a rabbit below to consider his next move as the falcon begins his descent?
Physics
2 answers:
Sergio [31]2 years ago
7 0
100m / 97.2m/s = 1.0288 seconds
attashe74 [19]2 years ago
5 0

Answer:

Time, t = 1.02 seconds

Explanation:

It is given that,

Velocity of bird, v = 97.2 m/s

If the falcon dives straight down from a height of 100 m, d = 100 m

We need to find the time this give a rabbit below to consider his next move as the falcon begins his descent. Time can be calculated as :

t=\dfrac{d}{v}

t=\dfrac{100\ m}{97.2\ m/s}

t = 1.02 seconds

Hence, this is the required solution.

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What is the minimum frequency of light necessary to emit electrons from titanium via the photoelectric effect?
erma4kov [3.2K]

<span>E = h x f </span>

<span>. . . then : </span>

<span>f = E / h </span>
<span>f = 4,41•10^-19 / 6,62•10^-34 </span>
<span>f = 6,66•10^14 Hz (s^-1) </span>


<span>b/ What is the wavelength of this light ? </span>
<span>- - - - - - - - - - - - - - - - - - - - - - - - - - - - </span>

<span>λ = c / f </span>
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4 0
2 years ago
Read 2 more answers
An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period o
Viktor [21]

Answer:

Spring constant, k = 24.1 N/m

Explanation:

Given that,

Weight of the object, W = 2.45 N

Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

Spring constant of the spring.

Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

m is the mass of object

m=\dfrac{W}{g}

m=\dfrac{2.45}{9.8}

m = 0.25 kg

k=\dfrac{4\pi^2m}{T^2}

k=\dfrac{4\pi^2\times 0.25}{(0.64)^2}

k = 24.09 N/m

or

k = 24.11 N/m

So, the spring constant of the spring is 24.1 N/m.

6 0
2 years ago
In a common but dangerous prank, a chair is pulled away as a person is moving downward to sit on it, causing the victim to land
sattari [20]

Answer:

a) Impulse |J|= 219.4 kgm/s

b) Force F = 2672 N

Explanation:

Given

Height of fall h = 0.50 m

Mass M = 70 kg

Period of collision t = 0.082 s

Solution

The final velocity of the person v is zero since the person will come to rest.

The initial velocity of the person can be calculated by using the "law of conservation of energy".

Initial Kinetic energy = Final potential energy

\frac{1}{2} mu^2=mgh\\\\u = \sqrt{2gh} \\\\u = \sqrt{2 \times 9.81 \times 0.50} \\\\u = 3.13 m/s

a) Impulse

J = final momentum - initial momentum

J = mv -mu\\\\J = 0 - (70 \times 3.13)\\\\J = -219.2 kgm/s

Magnitude of impulse

|J| = 219.1 kgm/s

b) Force

F = \frac{J}{t} \\\\F = \frac{219.1}{0.082} \\\\F = 2672 N

4 0
2 years ago
3. What conclusion can you make about the electric field strength between two parallel plates? Explain your answer referencing P
KIM [24]

Answer:

From the relation above we can conclude that the  as the distance between the two plate increases the electric field strength decreases

Explanation:

I cannot  find any attached photo, but we can proceed anyways theoretically.

The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point

i.e

E=\frac{F}{Q}

But the force F

F= \frac{kQ1Q2}{r^2}

But the electric field intensity due to a point charge Q at a distance r meters away is given by

E= \frac{\frac{kQ1Q2}{r^2}}{Q} \\\\\E= \frac{Q1}{4\pi er^2 }

<em>From the relation above we can conclude that the  as the distance between the two plate increases the electric field strength decreases</em>

6 0
2 years ago
A block with a mass of 9.00 kg is pulled at a constant speed across a horizontal tabletop with a spring scale. The scale reads 6
snow_tiger [21]

Answer:0.69

Explanation:

Coefficient of kinetic friction=f/R=61.8/90=0.69

7 0
2 years ago
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