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maxonik [38]
2 years ago
9

In ocean waves, water particles move ________ and energy moves ________.

Physics
2 answers:
morpeh [17]2 years ago
6 0
In ocean waves, water particles move with mechanical energy and energy moves with gravity

Not sure but hope it helps!
aniked [119]2 years ago
3 0

Answer:

In ocean waves, water particles move in circles and energy moves horizontally.

Explanation:

The formation of sea waves occurs with the action of the wind, which, when blowing over long distances, pushes the water until it generates these ripples. This type of wave is classified as mechanical, since it needs a means of propagation. In the waves of the ocean, water particles move in circles and energy moves horizontally.

Sea waves are formed in all possible directions on the high seas, but always reach the coast with the direction of propagation perpendicular to the beach, breaking in parallel in the sand.

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A boy of mass 80 kg slides down a vertical pole, and a frictional force of 480 N acts on him. What is his acceleration as he sli
olga_2 [115]

Answer:

His acceleration is \overrightarrow{a}=4\frac{m}{s^{2}}

Explanation:

Newton's second law states that acceleration of a body is cause by a net force, the relation between them is:

\sum\overrightarrow{F}=m\overrightarrow{a}

On the boy there're acting two forces, his weight (W) that points downward and the frictional force (f) that points upward (they boy moves downward and friction always is opposite to movement). So \sum\overrightarrow{F}=\overrightarrow{W}+\overrightarrow{f} so (1) is:

\overrightarrow{W}+\overrightarrow{f}=m\overrightarrow{a}

Using the positive direction downward weight and gravitational acceleration(g) are positive and friction force is negative:

W-f=m\overrightarrow{a}, solving for a:

\overrightarrow{a}=\frac{W-f}{m}, weight is mg:

\overrightarrow{a}=\frac{mg-f}{m}=\overrightarrow{f}=\frac{(80kg)(10\frac{m}{s^{2}})-(480)}{80}

\overrightarrow{a}=4\frac{m}{s^{2}}

6 0
2 years ago
PLEASE HELP!!!!!! WILL GIVE BRAINLIEST TO WHOEVER ANSWERS WITH THE RIGHT ANSWER !!!!!!!! 
Solnce55 [7]

It would be B and D your welcome


7 0
2 years ago
Read 2 more answers
before colliding, the momentum of block A is +15.0 kg m/s. after, block A has a momentum -12.0 kg*m/s. what is the momentum of b
Helen [10]

Answer:

The momentum of block B = 27 Kg m/s

Explanation:

Given,

The initial momentum of block A, MU = 15 Kg m/s

The final momentum of block A, MV = -12 Kg m/s

Consider the block B is initially at rest.

Therefore, the initial momentum of block B, mu = 0

According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.

                               <em> MU + mu = MV + mv</em>

                                15  +  (0) = (-12) + mv

                                         mv = 15 + 12

                                              =  27 Kg m/s

Hence, the momentum of the block B after impact is, mv = 27 Kg m/s

3 0
2 years ago
Write a hypothesis about how the height of the cylinder affects the temperature of the water. Use the "if . . . then . . . becau
IgorLugansk [536]

If the mass of the cylinder increases, the temperature of the water increases, because a greater mass means the cylinder has more potential energy that can be converted to thermal energy, increasing the temperature of the water.


4 0
2 years ago
A man is dragging a trunk up the loading ramp of a mover’s truck. The ramp has a slope angle of 20.0°, and the man pulls upward
AleksandrR [38]

Answer:

(a)  104 N

(b) 52 N

Explanation:

Given Data

Angle of inclination of the ramp: 20°

F makes an angle of 30° with the ramp

The component of F parallel to the ramp is Fx = 90 N.  

The component of F perpendicular to the ramp is Fy.

(a)  

Let the +x-direction be up the incline and the +y-direction by the perpendicular to the surface of the incline.  

Resolve F into its x-component from Pythagorean theorem:  

Fx=Fcos30°

Solve for F:  

F= Fx/cos30°  

Substitute for Fx from given data:  

Fx=90 N/cos30°

   =104 N

(b) Resolve r into its y-component from Pythagorean theorem:

     Fy = Fsin 30°

   Substitute for F from part (a):

     Fy = (104 N) (sin 30°)  

          = 52 N  

5 0
2 years ago
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