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Sonja [21]
2 years ago
13

A parent pushes a stroller with a 11.2 N force for 15.9 m. How much work did the parent do?

Physics
1 answer:
gayaneshka [121]2 years ago
7 0
The definition of work is that it is the Force applied over a distance, times the distance. The only trick is that you have to account only for forces in the direction of movement; any forces that are normal to the movement are not taken into account. Intuitively, work is generated only by forces that contribute  to the movement (or go against it; same or opposite direction).

Let us see now: W=F*d =11.2N* 15.9m=178.1 N*m=178.1 J where J stands for Joules. This is the work that the parent did, namely how much energy he had to put in to move the stroller.
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A car is pulled with a force of 10,000 N. The car's mass is 1267 kg. But, the car covers 394.6 m in 15 seconds
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A. Formula: F=ma or F/m=a

10,000N/1,267kg≈7.9m/s^{2}

B. Formula: a=\frac{V-V_{0} }{t} and s=d/t

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a=\frac{26.3-0}{15}

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A flashlight beam makes an angle of 60 degrees with the surface of the water before it enters the water. in the water what angle
alexira [117]
<h3><u>Answer</u>;</h3>

= 22°

<h3><u>Explanation</u>;</h3>
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  • Therefore; Sin i/Sin r = η

In this case; Angle of incidence = 90° -60° =30°, angle of refraction =? and η = 1.33

Thus;

Sin 30 / Sin r = 1.33

Sin r = Sin 30°/1.33

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2 years ago
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Mice21 [21]

Answer:

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Explanation:

Given;

acceleration of the truck, a_t = 12.7 m/s²

mass of the truck, m_t = 2490 kg

mass of the car, m_c = 890 kg

let the acceleration of the car at the moment they collided = a_c

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Magnitude of force exerted by the truck = Magnitude of force exerted by the car.

The force exerted by the car occurs in the opposite direction.

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