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1 year ago

A parent pushes a stroller with a 11.2 N force for 15.9 m. How much work did the parent do?

1 answer:

7 0

The definition of work is that it is the Force applied over a distance, times the distance. The only trick is that you have to account only for forces in the direction of movement; any forces that are normal to the movement are not taken into account. Intuitively, work is generated only by forces that contribute to the movement (or go against it; same or opposite direction).

Let us see now: W=F*d =11.2N* 15.9m=178.1 N*m=178.1 J where J stands for Joules. This is the work that the parent did, namely how much energy he had to put in to move the stroller.

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Dane is holding an 8 kilogram box 2 metres above the ground. How much energy is in the box's gravitational potential energy stor

9966 [12]

156.8 Joules of energy is in the box's gravitational potential energy store

Explanation:

Given:

Mass of the box Dane is holding = 8 Kilograms

Height at which Dane is holding the box above the ground= 2 metres

To Find:

Gravitational potential energy in the box=?

Solution:

gravitational potential energy is the work done per mass on a object to move that object from one fixed location to to another location against gravity.Its unit is joules or J

Thus Gravitational potential energy is represented as,

$PE_g=mgh$

where

$PE_g$ is the gravitational potential energy

m is the mass

h is the height

g is the gravitational force( 9.8 $m/s^2$ )

Now substituting the given values,

$PE_g=8\times 9.8\times 2$

$PE_g=156.8 Joules$

4 0

2 years ago

A long, thin straight wire with linear charge density λ runs down the center of a thin, hollow metal cylinder of radius R. The c

netineya [11]

Answer:

$E=\frac{\lambda}{2\pi r\epsilon_0}$

Explanation:

We are given that

Linear charge density of wire= $\lambda$

Radius of hollow cylinder=R

Net linear charge density of cylinder= $2\lambda$

We have to find the expression for the magnitude of the electric field strength inside the cylinder r<R

By Gauss theorem

$\oint E.dS=\frac{q}{\epsilon_0}$

$q=\lambda L$

$E(2\pi rL)=\frac{L\lambda}{\epsilon_0}$

Where surface area of cylinder= $2\pi rL$

$E=\frac{\lambda}{2\pi r\epsilon_0}$

8 0

1 year ago

Which trailer has more downward pressure where it attaches to the car?

VARVARA [1.3K]

The one that is loaded worst. The overall weight is not important; tongue weight is a matter of loading. Our 12,000 lb snow cat trailer, which has stops to position the cat properly, has under 100 lbs tongue weight. Excessive tongue weight is a Bad Thing because it reduces weight on the towing vehicle's front wheels, leading to instability.

4 0

1 year ago

The statements below are all true. Some of them represent important reasons why the giant impact hypothesis for the Moon’s forma

Molodets [167]

Answer:

the order of importance must be b e a f c

Explanation:

Modern theories indicate that the moon was formed by the collision of a bad plant with the Earth during its initial cooling period, due to which part of the earth's material was volatilized and as a ring of remains that eventually consolidated in Moon.

Based on the aforementioned, let's analyze the statements in order of importance

b) True. Since the moon is material evaporated from Earth, its compassion is similar

e) True. If the moon is material volatilized from the earth it must train a finite receding speed

a) True. The solar system was full of small bodies in erratic orbits that wander between and with larger bodies

f) False. The moon's rotation and translation are equal has no relation to its formation phase

c) false. The amount of vaporized material on the moon is large

Therefore, the order of importance must be

b e a f c

5 0

2 years ago

A bicyclist travels the first 800 m of a trip 1.4 minutes, the next 500 m in 1.6 minutes, and finishes up the final 1200 m in 2

soldier1979 [14.2K]

Answer:

v_average = 500 m / min

Explanation:

Average speed is defined

v = (x_{f} -x₀) / Δt

let's look in each section

section 1

the variation of the distance is 800 in a time of 1.4 min

v₁ = 800 / 1.4

v₁ = 571.4 m / min

section 2

distance interval 500 in a 1.6 min time interval

v₂ = 500 / 1.6

v₂ = 312.5 m / min

section 3

distance interval 1200 m in a time 2 min

v₃ = 1200/2

v₃ = 600 m / min

taking the speed of each section we can calculate the average speed

the distance traveled

Δx = 800 + 500 + 1200

Δx = 2500 m

the time spent

Δt = 1.4 + 1.6+ 2

Δt = 5 min

v_average = Δx / Δt

v_average = 2500/5

v_average = 500 m / min

7 0

2 years ago