According to Newton’s law of universal gravitation, which statements are true?
2 answers:
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Answer:
Minimum capacitance = 200 μF
Explanation:
From image B attached, we can calculate the current flowing through the capacitors.
Thus;
Since V=IR; I = V/R = 5/500 = 0.01 A
Maximum charge in voltage is from 5V to 4.9V. Thus, each capacitor will have 2.5V. Hence, change in voltage(Δv) for each capacitor will be ; Δv = 0.05 V
So minimum capacitance will be determined from;
i(t) = C(dv/dt)
So, C = i(t)(Δt/Δv) = 0.01[0.001/0.05]
C = 0.01 x 0.0002 = 200 x 10^(-6) F = 200 μF
Answer:
See explanation below
Explanation:
As I say in the comments, the question is incomplete, however, I will try to answer this by using data that I found on another site.
This is the part of the question that is not here:
If measurements are recorded to the nearest
tenth of a kilogram, find the fraction of these poodles
with weights
(a) over 9.5 kilograms;
(b) of at most 8.6 kilograms;
So, assuming a mean of 8 kg, and 0.9 of standard deviation, let X represents the weight of the poodles
The expression to calculate the fraction of poodle needed is:
Z = X - u / d
u: weight of the large number of poodle
d: standard deviation
Replacing data of a) wer have:
Z = 9.5 - 8 / 0.9
Z = 1.67
With this value, we need to take the value of Z, and see the area under the curve of standard deviation (see table attached)
Therefore:
P (X > 9.5) = P(Z > 1.67) = 0.5 - P (Z < 1.67) = 0.5 - 0.4525 = 0.0475
b) In this part, is the same as part a) so:
Z = 8.6 - 8 / 0.9 = 0.67
The value for area in the curve is 0.2486 so:
P = 0.5 + 0.2486 = 0.7486
Hope this helps
