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Alex17521 [72]
2 years ago
11

if one sprinter runs the 400.0 m in 58 seconds and another can run the same distance in 60.0 seconds, by how much distance will

the faster person win by if they race?
Physics
2 answers:
lbvjy [14]2 years ago
8 0

Answer:

The faster person wins by 13.31 m.

Explanation:

Given that,

For first person,

Times t_{1}=58\ sec

Distance d=400\ m

For second person,

Time t=60.0 sec

We need to calculate the speed of each person

Using formula of speed

For first person,

v=\dfrac{D}{t}

v=\dfrac{400}{58}

v=6.897\ m/s

For second person,

v=\dfrac{400}{60.0}

v=6.67\ m/s

We need to calculate the distance covered by second person in 58 sec

d=v\times t

d=6.667\times58

d=386.686\ m

So, Person wins by the distance

d=d_{A}-d_{B}

d=400.0-386.686=13.31\ m

Hence, The faster person wins by 13.31 m.

SCORPION-xisa [38]2 years ago
4 0

v = 400m/58s = 6.9m/s

v = 400m/60s = 6.7m/s

6.9m/s - 6.7m/s = .2m/s difference

60sec - 58 sec = 2 sec

v =Δx/t

Δx = vt

Δx = (.2m/s)(2sec)

Δx = .4m

therefore, the answer is .4m


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const2013 [10]

Answer:

388 cm^3

Explanation:

For this problem, we can use Boyle's law, which states that for a gas at constant temperature, the product between pressure and volume remains constant:

pV=const.

which can also be rewritten as

p_1 V_1 = p_2 V_2

In our case, we have:

p_1 = 75.9 kPa is the initial pressure

V_1 = 639 cm^3 is the initial volume

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Solving for V2, we find the final volume:

v_2 = \frac{p_1 V_1}{p_2}=\frac{(75.9)(639)}{125}=388 cm^3

7 0
2 years ago
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Setler [38]

Answer:

B. W is positive and a is negative

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As we know that the angular speed of the second clock is in positive direction so as it comes to halt from its initial direction of motion then we have

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\omega = positive

now it comes to stop so angular acceleration is taken in opposite to the direction of angular speed

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\alpha = negative

so here correct answer is

B. W is positive and a is negative

8 0
1 year ago
A sports car accelerates from 0 to 30 mph in 1.5 s. How long would it take to accelerate from 0 to 60 mph, assuming the power of
Crank

Answer:

6 s

Explanation:

given,

Sports car accelerate from 0 to 30 mph in 1.5 s

time taken to accelerate  0 to 60 mph = ?

The power of the engine is independent of velocity and neglecting friction

power =

P = constant  

the kinetic energy for 60 mph larger than this of 30 mph

 = \dfrac{\dfrac{1}{2}mv_1^2}{\dfrac{1}{2}mv_2^2}

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time = 4 x 1.5

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Answer:

The ball reaches Barney  head in  t = 8 \ s

Explanation:

From the question we are told that

 The rise velocity is  v  =  14.70 \  m/s

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Generally from kinematic equation  

   s = ut + \frac{1}{2} gt^2

Here s is the distance of the object from Barney head ,

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So

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6 0
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Answer:

14.4 m/s

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mass of Anna (Ma) = 68 kg

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We can find their speed (V) immediately after collision from the conservation of momentum where

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where V = speed immediately after collision

(68 x 17) + (76 + 12) = (68 + 76) x V

2068 = 144 V

V = 2068 / 144 = 14.4 m/s

8 0
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