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zalisa [80]
2 years ago
9

What was the vertical component of her acceleration during push-off? the positive direction is upward?

Physics
1 answer:
gladu [14]2 years ago
5 0
<span>The answer of these two problems are : A) a = (F-W)/m = (100-500)/500/g = 9.8*500/500 = +9.8 m/sec^2 B) a1 = +9.8-g = 0</span>
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The speed of sound in seawater is 1470 m/s. A dolphin sends out a click that reflects off of an
Nitella [24]

Answer: 0.204 s

Explanation:

The speed of sound V is defined as the distance traveled d in a especific time t:  

V=\frac{d}{t}  

Where:  

V=1470 m/s is the speed of sound  in seawater

t is the time the sound wave travels from the dolphin and then returns after the reflection

d=2(150 m) is twice the distance between the dolphin and the object to which the sound waves are reflected

Finding t:

t=\frac{d}{V}  

t=\frac{2(150 m)}{1470 m/s}

<u>Finally:</u>

t=0.204 s

3 0
2 years ago
Calculate time period of a simple pendulum if it takes 72 seconds to complete 24 oscillations
kipiarov [429]

72s for 24 complete oscillations.

Thus, a complete oscillation takes 72/24=3s

Answer: period T=3s

8 0
2 years ago
Sally finds herself stranded on a frozen pond so slippery that she can't stand up or walk on it. To save herself, she throws one
8_murik_8 [283]

Answer:

a) 2.5 m/s. (In the opposite direction to the direction in which she threw the boot).

b) The centre of mass is still at the starting point for both bodies.

c) It'll take Sally 12 s to reach the shore which is 30 m from her starting point.

Explanation:

Linear momentum is conserved.

(mass of boot) × (velocity of boot) + (mass of sally) × (velocity of Sally) = 0

5×30 + 60 × v = 0

v = (-150/60) = -2.5 m/s. (Minus inicates that motion is in the opposite direction to the direction in which she threw the boot).

b) At time t = 10 s,

Sally has travelled 25 m and the boot has travelled 300 m.

Taking the starting point for both bodies as the origin, and Sally's direction as the positive direction.

Centre of mass = [(60)(25) + (5)(-300)]/(60+5)

= 0 m.

The centre of mass is still at the starting point for both bodies.

c) The shore is 30 m away.

Speed = (Distance)/(time)

Time = (Distance)/(speed) = (30/2.5)

Time = 12 s

Hope this Helps!!!

7 0
2 years ago
Read 2 more answers
A housefly walking across a surface may develop a significant electric charge through a process similar to frictional charging.
Umnica [9.8K]

Answer:

Number of electrons, n=3.87\times 10^8\ electrons

Explanation:

Given that,

Charge on the fly, q=62\ pC=62\times 10^{-12}\ C

Let n is the number of electrons lose to the surface it is walking across. It is case of quantization of electric charge. It is given by :

q=ne

n=\dfrac{q}{e}

n=\dfrac{62\times 10^{-12}}{1.6\times 10^{-19}}

n = 387500000 electrons

or

n=3.87\times 10^8\ electrons

So, there are 3.87\times 10^8 electrons. Hence, this is the required solution.

3 0
2 years ago
A barbellbell is loaded with two 20 kg plates on its right side and two 20kg plates on its left side. The barbell is 2.2m long,
Aleks [24]

Answer:

<h2>Center of gravity of the system of all masses is 105 cm from the left end of the rod</h2>

Explanation:

Let the position of Left end of the rod is our reference

So here we will have

m_1 = 20 kg

x_1 = 20 cm

m_2 = 20 kg

x_2 = 30 cm

m_3 = 20 kg

x_3 = 110 cm

m_4 = 20 kg

x_4 = (220 - 40) = 180 cm

m_5 = 20 kg

x_5 = (220 - 35) = 185 cm

so we will have

x_{cm} = \frac{m_1x_1 + m_2x_2 + m_3x_3 + m_4x_4 + m_5x_5}{m_1 + m_2 + m_3 + m_4 + m_5}

x_{cm} = \frac{20(20 + 30 + 110 + 180 + 185)}{20 + 20 + 20 + 20 + 20}

x_{cm} = 105 cm

7 0
2 years ago
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