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Answer:
326.25 kWh
Explanation:
Efficiency of a machine is defined as the ratio of useful energy to that of the energy consumed by the machine.
Here, efficiency is given as 87% and the energy consumed by the computer is 375 kWh.
Efficiency, 
Plug in the values of 
and 375 kWh for energy consumed. Solve for useful energy. This gives,
Efficiency, 
Therefore, the useful energy provided by the computer is 326.25 kWh.
Calculate for the x and y-components of the velocities involved in this item.
2 mi/h (45° east)
x-component = (2 mi/h)(sin 45°)
= 1.41 mi/h
y-component = (2 mil/h)(cos 45°)
= 1.41 mi/h
4 mi/h (east)
x-component = 4 mi/h
y-component = 0 mi/h
Adding up the corresponding components:
x-component = 5.4142 mi/h
y-component = 1.4142 mi/h
Calculating for the resultant,
R = sqrt ((x²) + (y²))
R = sqrt ((5.4142 mi/h)² + (1.4142 mi/h)²)
R = 5.60 mi/h
Answer: 5.6 mi/h
<span>When the question says the ball lands a distance of 235 meters from the release point, we can assume this means the horizontal distance is 235 meters.
Let's calculate the time for the ball to fall 235 meters to the ground.
y = (1/2)gt^2
t^2 = 2y / g
t = sqrt{ 2y / g }
t = sqrt{ (2) (235 m) / (9.81 m/s^2) }
t = 6.9217 s
We can use the time t to find the horizontal speed.
v = d / t
v = 235 m / 6.9217 s
v = 33.95 m/s
Since the horizontal speed is the speed of the plane, the speed of the plane is 33.95 m/s</span>
