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Tema [17]
2 years ago
8

Cathode ray tubes in old television sets worked by accelerating electrons and then deflecting them with magnetic fields onto a p

hosphor screen. The magnetic fields were created by coils of wire on either side of the tube carrying large currents. In one such TV set, the phosphor screen is 51.2 cm wide, and is 11.1 cm away from the center of the magnetic deflection coils (that is, the center of the region of magnetic field). The electron beam is first accelerated through a 22,000 V potential difference before it enters the magnetic field region, which is 1.00 cm wide. The field is approximately uniform and perpendicular to the velocity of the electrons. If the field were turned off, the electrons would hit the center of the screen. What magnitude of magnetic field (in mT) is needed to deflect the electrons so that they hit the far edge of the screen

Physics
1 answer:
Roman55 [17]2 years ago
3 0

Answer:

B = 0.046T

Explanation:

given

size of the screen = 51.2cm

distance from center = 11.1cm

region of magnetic field = 1.00cm

V= 22000V= 22kV

 

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Fittoniya [83]

Answer:

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Explanation:

From the question we are told that  

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   Now  this voltage can be  mathematical represented as

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Where  RC  is the time constant

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    \frac{V_o}{2}  =  V_o  *  e ^{-\frac{3.40 *10^{-3}}{RC} }

    0.5  =  e^{-\frac{3.40 *10^{-3}}{RC} }

    - \frac{0.5}{RC}  =  ln (0.5)

     -\frac{0.5}{RC} =  -0.6931

     RC  =  0.721

Generally the cross-over frequency for a low pass filter is mathematically represented as

          f  = \frac{1}{2 \pi  * RC  }

substituting values  

           f  = \frac{1}{2*  3.142  * 0.72  }

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7 0
1 year ago
2. Turn off the Parallel line and turn on the Line through focal point. Move the light bulb around. What do you notice about the
MArishka [77]

Answer:

The group of light rays is reflected back towards  the focal point thereby producing a magnifying effect.

Explanation:

8 0
2 years ago
Two small aluminum spheres, each of mass 0.0250 kilograms, areseparated by 80.0 centimeters.
sineoko [7]

Answer:

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electrons removed from each sphere

N = 5.27 \times 10^{15}

Fraction of electrons transferred is given as

f = 7.27 \times 10^{-10}

Explanation:

As we know that moles is defined as

n =\frac{mass}{molar mass}

n = \frac{0.0250}{0.026982}

n = 0.93

so number of atoms of Al in each sphere is given as

N = 0.93(6.02 \times 10^{23})

N = 5.58 \times 10^{23}

Now number of electrons in each atom is given as

atomic number = number of electrons in each atom = 13

total number of electrons in each sphere is

N = 13 \times (5.58 \times 10^{23})

N = 7.25 \times 10^{24}

Also we know that force of attraction between them is given as

F= \frac{kq_1q_2}{r^2}

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q = Ne

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Fraction of electrons transferred is given as

f = \frac{5.27 \times 10^{15}}{7.25 \times 10^{24}}

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6 0
1 year ago
A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to
erastovalidia [21]
Would presume you are asked to find the volume, since there is no second volume.

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7 0
2 years ago
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uranmaximum [27]

Since the tower base is square with a side length of  125 m,

Therefore,

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=1.225\ kg/m^3 \times 7948168.803\ m^3=9736506.78\ kg

Hence, the mass of the air in the cylinder is this more  than the mass of the tower.


4 0
1 year ago
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