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IRISSAK [1]
2 years ago
5

A beaker contain 200mL of water What is its volume in cm3 and m3

Physics
2 answers:
Bogdan [553]2 years ago
7 0
The volumes are 200cm3 and 0.0002m3
Nutka1998 [239]2 years ago
4 0
A mL is equal to a cm^3, so it is 200 cm^3. To help you transfer cm^3 to m^3, use KHDBDCM. You move the decimal point twice to the left which means that it is 2 m^3.
TLDR: 200 cm^3 and 2 m^3.
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Which statements accurately describe conduction and convection? Check all that apply.
Gwar [14]

Answer:

Both conduction and convection need matter to transfer thermal energy.

Conduction involves collision of particles, while convection involves the movement of a liquid or gas.

Explanation:

There are three ways in which heat is transmitted:

  1. By Conduction, when the transmission is by the direct contact (through collisions).

   2. By Convection, heat transfer in fluids making a current created by less dense fluids floating and more dense fluids sinking (like water or the air, for example).  

  3. By Radiation, by the electromagnetic waves (they can travel through any medium and in vacumm)

Therefore, both conduction and convection need matter to transfer thermal energy (unlike radiation).

4 0
2 years ago
Read 2 more answers
An object’s velocity is measured to be vx(t) = α - βt2, where α = 4.00 m/s and β = 2.00 m/s3. At t = 0 the object is at x = 0. (
Leona [35]

Answer:

Explanation:

Given

v_x(t)=\alpha -\beta t^2

\alpha =4\ m/s

\beta =2\ m/s^3

v_x(t)=4-2t^2

v=\frac{\mathrm{d} x}{\mathrm{d} t}

\int dx=\int \left ( 4-2t^2\right )dt

x=4t-\frac{2}{3}t^3

acceleration of object

a=\frac{\mathrm{d} v}{\mathrm{d} t}

a=-4t

(b)For maximum positive displacement velocity must be zero at that instant

i.e.v=0

4-2t^2=0

t=\pm \sqrt{2}

substitute the value of t

x=4\times \sqrt{2}-\frac{2}{3}\times 2\sqrt{2}

x=3.77\ m

7 0
2 years ago
A solenoid that is 35 cm long and contains 450 circular coils 2.0 cm in diameter carries a 1.75-A current. (a) What is the magne
Taya2010 [7]

Answer:

Explanation:

a )  No of turns per metre

n = 450 / .35

= 1285.71

Magnetic field inside the solenoid

B = μ₀ n I

Where I is current

B = 4π x 10⁻⁷ x 1285.71 x 1.75

= 28.26 x 10⁻⁴ T

This is the uniform magnetic field inside the solenoid.

b )

Magnetic field around a very long wire at a distance d is given by the expression

B = ( μ₀ /4π ) X 2I / d

= 10⁻⁷ x 2 x ( 1.75 / .01 )

= .35 x 10⁻⁴ T

In the second case magnetic field is much less. It is due to the fact that in the solenoid magnetic field gets multiplied due to increase in the number of turns. In straight coil this does not happen .

6 0
2 years ago
Read 2 more answers
An object is thrown with an initial speed v near the surface of Earth. Assume that air resistance is negligible and the gravitat
IgorLugansk [536]

Answer:

E. downward and constant

Explanation:

Freefall is a special case of motion with constant acceleration because the acceleration due to gravity is always constant and downward. This is true even when an object is thrown upward or has zero velocity.

For example, when a ball is thrown up in the air, the ball's velocity is initially upward. Since gravity pulls the object toward the earth with a constant acceleration ggg, the magnitude of velocity decreases as the ball approaches maximum height. At the highest point in its trajectory, the ball has zero velocity, and the magnitude of velocity increases again as the ball falls back toward the earth.

3 0
2 years ago
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A solid steel cylinder is standing (on one of its ends) vertically on the floor. The length of the cylinder is 3.2 m and its rad
maksim [4K]

To solve this problem it is necessary to apply the concepts related to Young's Module and its respective mathematical and modular definitions. In other words, Young's Module can be expressed as

\Upsilon = \frac{F/A}{\Delta L/L_0}

Where,

F = Force/Weight

A = Area

\Delta L= Compression

L_0= Original Length

According to the values given we have to

\Upsilon_{steel} = 200*10^9Pa

\Delta L = 5.6*10^{-7}m

L_0 = 3.2m

r= 0.59m \rightarrow A = \pi r^2 = \pi *0.59^2 = 1.0935m^2

Replacing this values at our previous equation we have,

\Upsilon = \frac{F/A}{\Delta L/L_0}

200*10^9 = \frac{F/1.0935}{5.6*10^{-7}/3.2}

F = 38272.5N

Therefore the Weight of the object is 3.82kN

4 0
2 years ago
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