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Zepler [3.9K]
2 years ago
7

Compare the benefits of wildfires to grasslands, northern forests, and deciduous forests.

Physics
2 answers:
Dimas [21]2 years ago
6 0
Wildfires benefit grasslands, northern forests, and deciduous forests. Grasslands are benefited by improved soil quality and control of tree cover. Invertebrate species diversity is maintained through wildfire as well. Northern forests, like grasslands, experience increased production and nutritional quality of food as a result of wildfires. Deciduous forests experience an increase in the nutritional quality of food as well, but the effects are more temporary. The amount of shrubs in deciduous forests is reduced as a result of wildfires, allowing more herbaceous plants such as mosses and lichens to grow.
zhannawk [14.2K]2 years ago
6 0

Wildfires benefit grasslands, northern forests, and deciduous forests. Grasslands are benefited by improved soil quality and control of tree cover. Invertebrate species diversity is maintained through wildfire as well. Northern forests, like grasslands, experience increased production and nutritional quality of food as a result of wildfires. Deciduous forests experience an increase in the nutritional quality of food as well, but the effects are more temporary. The amount of shrubs in deciduous forests is reduced as a result of wildfires, allowing more herbaceous plants such as mosses and lichens to grow.

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Two small balls, A and B, attract each other gravitationally with a force of magnitude F. If we now double both masses and the s
Nimfa-mama [501]

Answer:

D) F

Explanation:

Let m and M be the mass of the balls A and B respectively and r be the distance between the two balls. The magnitude of attractive gravitational force experienced by the balls due to each other is given by the relation :

F=\frac{GMm}{r^{2} }      ......(1)

Now, if the masses of both the balls gets doubled as well as there separation distance also gets doubled, then let F₁ be the new gravitational force acting on them.

Since, New mass of ball A = 2M

           New mass of ball b = 2m

Distance between the two balls = 2r

Substitute these values in equation (1).

F_{1} =\frac{G(2M)(2m)}{(2r)^{2} }

F_{1} =\frac{4GMm}{4r^{2} }=\frac{GMm}{r^{2} }

Using equation (1) in the above equation.

F₁ = F

4 0
1 year ago
A steady circular __________ light means drivers must stop at a marked stop line.
elixir [45]
B. red................
5 0
2 years ago
Read 2 more answers
From Kepler's third law, an asteroid with an orbital period of 8 years lies at an average distance from the Sun equal to:
bazaltina [42]

Answer:

The correct option is (B).

Explanation:

The Kepler's third law of motion gives the relationship between the orbital time period and the distance from the semi major axis such that,

T^2\propto a^3\\\\T^2=ka^3

It is mentioned that, an asteroid with an orbital period of 8 years. So,

(8)^2=ka^3\\\\64=ka^3\\\\a=(64)^{\dfrac{1}{3}}\\\\a=4\ AU

So, an asteroid with an orbital period of 8 years lies at an average distance from the Sun equal to 4 astronomical units.

7 0
1 year ago
Trace fossils are recognized as evidence of which pre-existing life? plants plants and animals neither plants nor animals animal
photoshop1234 [79]

Answer:

a fossil of a footprint, trail, burrow, or other trace of an animal rather than of the animal itself.

Explanation:

Trace fossils are the indirect evidence of life in the past, such as the footprints, tracks, burrows, borings, and feces left behind by animals, rather than the preserved remains of the actual animal body itself.

Fossil is the naturally preserved remains of plants and animals which somehow get trapped in amber, hair, petrified wood, oil, coal, and DNA remnants.

5 0
2 years ago
Read 2 more answers
What is the rate of heat transfer by radiation, with an unclothed person standing in a dark room whose ambient temperature is 22
SIZIF [17.4K]

Answer:

5.45\times 10^{-4} W

Explanation:

T_{r} = Temperature of the room = 22.0 °C = 22 + 273 = 295 K

T_{s} = Temperature of the skin = 33.0 °C = 33 + 273 = 306 K

A = Surface area = 1.50 m²

\epsilon = emissivity = 0.97

\sigma = Stefan's constant = 5.67 x 10⁻⁸ Wm⁻² K⁻⁴

Rate of heat transfer is given as

R = \epsilon \sigma A (T_{s}^{2} - T_{r}^{2})

R = (0.97)(5.67\times 10^{-8}) (1.50) ((306)^{2} - (295)^{2})

R = 5.45\times 10^{-4} W

3 0
2 years ago
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